From the following design information for a circular curve: R = 760.00 ft.; delta = 12 degrees 04 minutes 15 seconds; Sta. @ BC = 9+63.04 What is the deflection angle (from the BC) to sta. 10+80?

University Physics Volume 1
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Chapter10: Fixed-axis Rotation
Section: Chapter Questions
Problem 10CQ: In circular motion, a tangential acceleration can change the magnitude of the velocity but not its...
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From the following design information for a circular curve: R = 760.00 ft.; delta = 12
degrees 04 minutes 15 seconds; Sta. @ BC = 9+63.04 What is the deflection angle
(from the BC) to sta. 10+80?
a. Deflection angle = 04 degrees 24 minutes 32 seconds
O b. Deflection angle = 08 degrees 49 minutes 06 seconds
c. Deflection angle = 08 degrees 48 minutes 06 seconds
d. Deflection angle = 04 degrees 24 minutes 03 seconds
Transcribed Image Text:From the following design information for a circular curve: R = 760.00 ft.; delta = 12 degrees 04 minutes 15 seconds; Sta. @ BC = 9+63.04 What is the deflection angle (from the BC) to sta. 10+80? a. Deflection angle = 04 degrees 24 minutes 32 seconds O b. Deflection angle = 08 degrees 49 minutes 06 seconds c. Deflection angle = 08 degrees 48 minutes 06 seconds d. Deflection angle = 04 degrees 24 minutes 03 seconds
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