Answer all part please i will rate Full time college students report spending a mean of 25 hours per week on academic activities, both inside and outside the classroom. Assume the standarddeviation of time spent on academic activities is 6 hours. Complete parts (a) through (d) belowweekr7486 (Round to four decimal places as needed)b. If you select a random sample of 16 full-time college students, there is an 86% chance that the sample mean is less than how manny hours per week?D(Round to two decimal places an needed)c. What assumption must you make in order to solve (a) and (b?O A. The population is normally distributedO B. The sample is symmetrically distributed, such that the Central Limit Theorem will kely holdOC. The population is uniformly distributedOD. The population is symmetrically distributed such that the Central Limit Theorem will likely hold for samples of size 16d. If you select a random sample of 100 ful-time college students, there is an 86% chance that the sample mean is less than how many hours per week?Round to two decimal places as needed)

* ANSWER :- b) z value at 86% = 1.08 z = (x - mean)/s 1.08 = (x - 25)/1 x = 1.08 * 1 + 25 x =…

Full time college students report spending a mean of 25 hours per week on academic activities, both inside and outside the classroom. Assume the standard deviation of time spent on academic activities is 6 hours. Complete parts (a) through (d) below weekr 7486 (Round to four decimal places as needed) b. If you select a random sample of 16 full-time college students, there is an 86% chance that the sample mean is less than how many hours per week? D(Round to two decimal places as needed) c. What assumption must you make in order to solve (a) and (b? O A. The population is normally distributed OB. The sample is symmetrically distributed, such that the Central Limit Theorem will kely hold OC. The population is uniformly distributed OD. The population is symmetrically distributed such that the Central Limit Theorem will likely hold for samples of size 16. d. If you select a random sample of 100 ful-time college students, there is an 86% chance that the sample mean is less than how many hours per week? Round to two decimal places as needed)

Full time college students report spending a mean of 25 hours per week on academic activities, both inside and outside the classroom. Assume the standard deviation of time spent on academic activities is 6 hours. Complete parts (a) through (d) below weekr 7486 (Round to four decimal places as needed) b. If you select a random sample of 16 full-time college students, there is an 86% chance that the sample mean is less than how many hours per week? D(Round to two decimal places as needed) c. What assumption must you make in order to solve (a) and (b? O A. The population is normally distributed OB. The sample is symmetrically distributed, such that the Central Limit Theorem will kely hold OC. The population is uniformly distributed OD. The population is symmetrically distributed such that the Central Limit Theorem will likely hold for samples of size 16. d. If you select a random sample of 100 ful-time college students, there is an 86% chance that the sample mean is less than how many hours per week? Round to two decimal places as needed)

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

See similar textbooks

Similar questions

Of 900 people treated with a new drug, 180 show allergic reaction. Construct a 98% confidence interval for the true proportion of the population who would show an allergic reaction.
Let x be a random variable representing dividend yield of Australian bank stocks. We mayassume that x has a normal distribution with σ = 2.4%. A random sample of 15 Australianbank stocks has a sample mean of x = 6.83%. For the entire Australian stock market, themean dividend yield is μ = 6.9%. Do these data indicate that the dividend yield of allAustralian bank stocks is higher than 6.9%? Use α = 0.05. What is the value of the teststatistic?
Sixty percent (60%) of Students of the Reginal College were took French. Fifteen (15) were randomly and independently sampled. a) Calculate the probability that at most 2 out of the 15 randomly selected students took French. b) Of the 15 students, how many do you expect to take French.
Suppose employers care about overall productivity Z, which is made up of two components, X and Y, such that Z=X+Y (and employers know this productivity function). Suppose there are two groups (male and female) whose average Zs are the same (i.e. Z_M =Z_F), but X_M < X_F and Y_M > Y_F (and again, employers know these population averages). Researchers decide to run a resume-based audit study where they randomize names based on gender (using typically male or female names) but hold constant Y. They provide no information on X. Which of the following would suggest taste-based discrimination? ● The call-back rate is the same for both sexes. ● The call-back rate is higher for men than for women ● We can't use differences in call-back rates to find suggestive evidence of taste-based discrimination because there's too many other factors that are different across the resumes. ● The call-back rate is higher for women than for men
What is the probability that a waiter will refuse to serve alcoholic beverages to only 2 minors if she randomly checks the IDs of 5 students from among 9 students of which 4 are not of legal age?
senior accounting major at Midsouth State University has job offers from four CPA firms. To explore the offers further, she asked a sample of recent trainees how many months each worked for the firm before receiving a raise in salary. The sample information is submitted to Minitab with the following results: Analysis of Variance Source df SS MS F P Factor 3 28.17 9.39 5.37 0.010 Error 15 26.26 1.75 Total 18 54.43 What is the decision rule? (Round your answer to 2 decimal places.) At the 0.05 level of significance, is there a difference in the mean number of months before a raise was granted among the four CPA firms?
PLS ANSWER Q5 and Q6
One hundred persons were asked, "Do you favour regional integration?". Of the 35 that answered "no" to the question, 14 were female. Of the 65 that answered "yes" to the question, 30 were female.a)Draw a completed contingency table, showing totals, to illustrate the information above. b)If one person was randomly selected, what is the probability that the person is:(i) female? (ii) female or responded “no”? (iii) female given that they responded “no”?
Consider the mean cost of getting a four-year college degree. The middle interval which captures 95% of mean costs from samples of n = 75 graduates is (x̅₁, x̅₂) = $60,142 $68,446 25 What is the population mean cost of getting a college degree? a $62,384 b $63,014 c $63,651 d $64,294
18. Car and Taxi Ages When the author visited Dublin, Ireland (home of Guinness Breweryemployee William Gosset, who first developed the t distribution), he recorded the ages of randomlyselected passenger cars and randomly selected taxis. The ages can be found from thelicense plates. (There is no end to the fun of traveling with the author.) The ages (in years) arelisted below. We might expect that taxis would be newer, so test the claim that the mean age ofcars is greater than the mean age of taxis.
Suppose you select a random sample of 16 students from a population that has mean of µ = 75 and standard deviation of ơ = 20. You want to know what would be considered a ‘typical’ sample mean for a sample of n = 16. To answer your question, you compute the two sample means that define the middle 95% of the distribution of sample means. Show your work, sketch the distribution, and shade in the area of interest. Hint: Sample means that are in the extreme 5% of the distribution (2.5% in each tail of the distribution) are considered ‘atypical’ or ‘extreme.’
The probability of a sample proportion this high coming from a population where the true proportion of Pennsylvanians with a high school diploma is 83% is 0.0228. How convincing is this probability in convincing us that the true proportion of Pennsylvanians with a high school diploma is greater than 0.83?