GAUSS'S LAW TO CHARGE INSULATORS: Gauss's law is useful in determining electric fields when the charge distribution is characterized by a high degree of symmetry. The following examples demonstrate ways of choosing the gaussian surface over which the surface integral can be simplified and the electric field determined. In choosing the surface, we should always take advantage of the symmetry of the charge distribution so that we can remove E from the integral and solve for it. The goal in this type of calculation is to determine a surface that satisfies one or more of the following conditions: 1. The value of the electric field can be argued by symmetry to be constant over the surface. 2. The dot product can be expressed as a simple algebraic product E dA because E and dA are parallel. 3. The dot product is zero because E and dA are perpendiculars.

University Physics Volume 2
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Chapter6: Gauss's Law
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Problem 86AP: Two non-conducting spheres of radii R1 and R2 are uniformly charged with charge densities p1 and p2...
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GAUSS'S LAW TO CHARGE INSULATORS:
Gauss's law is useful in determining electric fields when the charge
distribution is characterized by a high degree of symmetry. The following examples
demonstrate ways of choosing the gaussian surface over which the surface integral
can be simplified and the electric field determined. In choosing the surface, we should
always take advantage of the symmetry of the charge distribution so that we can
remove E from the integral and solve for it. The goal in this type of calculation is to
determine a surface that satisfies one or more of the following conditions:
1. The value of the electric field can be argued by symmetry to be constant
over the surface.
2. The dot product can be expressed as a simple algebraic product E dA
because E and dA are parallel.
3. The dot product is zero because E and dA are perpendiculars.
4. The field can be argued to be zero over the surface.
Transcribed Image Text:GAUSS'S LAW TO CHARGE INSULATORS: Gauss's law is useful in determining electric fields when the charge distribution is characterized by a high degree of symmetry. The following examples demonstrate ways of choosing the gaussian surface over which the surface integral can be simplified and the electric field determined. In choosing the surface, we should always take advantage of the symmetry of the charge distribution so that we can remove E from the integral and solve for it. The goal in this type of calculation is to determine a surface that satisfies one or more of the following conditions: 1. The value of the electric field can be argued by symmetry to be constant over the surface. 2. The dot product can be expressed as a simple algebraic product E dA because E and dA are parallel. 3. The dot product is zero because E and dA are perpendiculars. 4. The field can be argued to be zero over the surface.
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