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Genetic application problems
Two men (Father 1 and Father 2) claim in court the paternity of a child, whose blood group is 0. The mother is from group A, while the possible father 1 is from B and the possible father 2 is from AB. Please explain if this information can be used to indicate which of them is not your father. Come up with possible genotypes for the child, mother, and parents. Explain...
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- Genetic application problems A woman with blood group 0 has had a child with blood group A. What is the child's genotype? And the phenotype of the father? Explain...Genetic application problems How can they be the children of a man from group A, whose mother was from group O, and a woman from group B, whose father was from group O? Make a well done crossbreeding scheme. Explain...Genetic application problem A couple in which the woman belongs to group 0 Rh- and the man is AB Rh + claim as theirs a baby whose blood is A Rh +. What would you think as a judge about this lawsuit? Explain...
- Genetics in Practice case studies are critical-thinking exercises that allow you to apply your new knowledge of human genetics to real-life problems. Case study Michelle was a 42-year-old woman who had declined counselling and amniocentesis at 16 weeks of pregnancy but was referred for genetic counseling after an abnormal ultrasound at 20 weeks of gestation. After the ultrasound, a number of findings suggested a possible chromosome abnormality in the fetus. The ultrasound showed swelling under the skin at the back of the fetuss neck; shortness of the femur, humerus, and ear length; and underdevelopment of the middle section of the fifth finger. Michelles physician performed an amniocentesis and referred her to the genetics program. Michelle and her husband did not want genetic counseling before receiving the results of the cytogenetic analysis. This was Michelles third pregnancy; she and her husband, Mike, had a 6-year-old daughter and a 3-year-old son. At their next session, the counselor informed the couple that the results revealed trisomy 21, explored their understanding of Down syndrome, and elicited their experiences with people with disabilities. She also reviewed the clinical concerns revealed by the ultrasound and associated anomalies (mild to severe intellectual disability, cardiac defects, and kidney problems). The options available to the couple were outlined. They were provided with a booklet written for parents making choices after the prenatal diagnosis of Down syndrome. After a week of careful deliberation with their family, friends, and clergy, they elected to terminate the pregnancy. Should physicians discourage a 42-year-old woman from having children because of an increased chance of a chromosomal abnormality?Calculation problem on genetics. What would be the formula?Question:- Based on your selected mode of inheritance, show the genotypes for the following individuals. [Use these symbols for alleles: if it is autosomal, then use the symbols B - dominant, b - recessive (e.g. BB, bb etc.) if it is X-Linked, then X(B) - dominant, X(b) - recessive, and Y for Y-chromosome (e.g. X(B)X(B), X(B)Y etc.) ] I-1 I-2 II-7 II-8 III-10 III-11 III-12 IV-8 IV-9
- Practice Pedigree Problem help. I am confused so please show. Label Phenotypes and genotypes as you go about the Pedigree (and whatever else might be required)! Thank you again for your help, these questions confuse me). Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individuals which are heterozygous for these alleles are calico or tortiseshell in color. a). If a long-haired, black male is mated with a calico female homozygous for short hair, what kind of kittens will be produced in the F1generation? Give both genotypes and phenotypes; express the genotypes both symbolically and in words.Question:- The success of renal transplantation depends on three human histocompatibility genes, HLA-A, HLA-B and HLA-C, which must match between the donor and the receiver. A single mismatch may cause the kidney rejection. Each gene has multiple co-dominant alleles. These three genes are located very close to each other on chromosome 6, so that the recombination rate is very low (below 1%). The father has the following genotype: A1, A2, B24, B10, Cw4 and Cw7 and the mother is A1, A1, B11, B7, Cw5 and Cw8. Their first boy is A1, A1, B24, B11, Cw7 and Cw8. What is the probability that the second child is compatible with his/her brother?Sample problems related to non Mendelian inheritanceRead, analyze and answer completely the following problems: 1. Explain why it is possible for the proband in the following pedigree to have children of blood types A, B, and AB. Considering epistatic genes, what are the possible genotypes of II-2? 2. Agouti (A) is wild type and produces alternating bands of pigment on each hair. Black (a) is recessive to agouti. A mutation on gene B (recessive b) can eliminate all color. In a cross between agouti (AABB) and albino (aabb) mice, what genotypes, phenotypes, and proportions are expected in the offspring in F1 and F2 generations?
- Subject: Genetic problems 6. how would you recognize a line of garden peas that had become genotypically pure for a given trait? 7. A cross of two pink-flowered plants produces offspring whose flowers are red, pink, or white. Defining your genetic symbols, give all the different kinds of genotypes involved, and the phenotypes they represent. 9. In snapdragons, red flowers (R) are incompletely dominant to white (r), the hybrid being pink; narrow leaves (N) are incompletely dominant to broad leaves (n), the hybrid being intermediate in width ("medium"). show the genotypes and phenotypes for the progeny of a cross between a. red medium and pink medium plant b. a pink medium and white narrow c. two identical dihybrids 12. In guinea pigs, short is dominant to long. A short-haired guinea pig was mated to a long-haired one. What proportions of the offspring (F1) will be expected to be: a. homozygous short-haired b. homozygous long -haired c. heterozygous short-haired d. heterozygous…Complementation tests of distinct recessive mutants, 1 through 8, produce the data in the matrix below. A plus (+) indicates complementation, meaning the phenotype of the combined alleles is wild type, and a minus (-) indicates a failure to complement meaning that a mutant phenotype results. Assume that the missing mutant combinations would yield data consistent with the entries that are shown. How many complementation groups are formed by these eight mutants? (Picture attached) A) 2 B) 3 C) 4 D) 5 E) 6polygenic trait mating 2 An AaBBCcdd male mates with an AaBbCCDD female. 1. What is the maximum number of ridge-producing genes possible in one of the children? 2. What would be the TRC for this child if it is a male? 3. What is the minimum number of ridge-producing genes possible in a child of this couple? 4. If this child were a female, would she have a higher or lower TRC than the parent with the lower ridge count? A. lower B. higher C. equal