Genetics Problem Solving Crosses Involving Multiple Alleles Step 4 Combine the gamete genotypes of one parent with those of the other parent to show all pa offspring genotypes. [A |A|A I^i 18 1+1 B 1 Bi Step 5 State the genotype and phenotype ratios of the offspring. 1 : 1 : 1P18:11³ = 14 1P, 41, 4P8, 1418 2 type A: 1 type AB: 1 type B = 1/2 type A, 14 type AB, 4 type B EXERCISES For each exercise draw the Punnett square when appropriate and answer the questions in the spaces provic 1. A woman homozygous for type B blood marries a man who is heterozygous type A. What will be t possible genotypes and phenotypes of their children? 2. A man with type O blood marries a woman with type AB blood. What will be the possible genotyp- and phenotypes of their children? 3. A type B woman whose mother was type O marries a type O man. What will be the possible genot- and phenotypes of their children? -. A type A woman whose father was type B marries a type B man whose mother was type A. What wil their childrens' possible genotypes and phenotypes? . What is the probability that a couple whose blood types are AB and O will have a type A child? - A couple has a child with type A blood. If one parent is type O, what are the possible genotypes of other parent?

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter4: Pedigree Analysis In Human Genetics
Section: Chapter Questions
Problem 19QP: Analysis of X-Linked Dominant and Recessive Traits Suppose a couple, both phenotypically normal,...
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Name
ENRICHMENT ACTIVITY (continued)
Genetics Problem Solving Crosses Involving Multiple Alleles
25
Step 4
Combine the gamete genotypes of one parent with those of the other parent to show all possible
offspring genotypes.
14
JAJA I^i
|8 [+18 1Bi
Step 5 State the genotype and phenotype ratios of the offspring.
1 : 1 Pi: 1118: 118 = 141, 141, 148, 1418
2 type A: 1 type AB: 1 type B = 1/2 type A, 14 type AB, 4 type B
CHAPTER
EXERCISES
For each exercise draw the Punnett square when appropriate and answer the questions in the spaces provided.
1. A woman homozygous for type B blood marries a man who is heterozygous type A. What will be the
possible genotypes and phenotypes of their children?
2. A man with type O blood marries a woman with type AB blood. What will be the possible genotypes
and phenotypes of their children?
3. A type B woman whose mother was type O marries a type O man. What will be the possible genotypes
and phenotypes of their children?
4. A type A woman whose father was type B marries a type B man whose mother was type A. What will be
their childrens' possible genotypes and phenotypes?
5. What is the probability that a couple whose blood types are AB and O will have a type A child?
6. A couple has a child with type A blood. If one parent is type O, what are the possible genotypes of the
other parent?
Transcribed Image Text:Name ENRICHMENT ACTIVITY (continued) Genetics Problem Solving Crosses Involving Multiple Alleles 25 Step 4 Combine the gamete genotypes of one parent with those of the other parent to show all possible offspring genotypes. 14 JAJA I^i |8 [+18 1Bi Step 5 State the genotype and phenotype ratios of the offspring. 1 : 1 Pi: 1118: 118 = 141, 141, 148, 1418 2 type A: 1 type AB: 1 type B = 1/2 type A, 14 type AB, 4 type B CHAPTER EXERCISES For each exercise draw the Punnett square when appropriate and answer the questions in the spaces provided. 1. A woman homozygous for type B blood marries a man who is heterozygous type A. What will be the possible genotypes and phenotypes of their children? 2. A man with type O blood marries a woman with type AB blood. What will be the possible genotypes and phenotypes of their children? 3. A type B woman whose mother was type O marries a type O man. What will be the possible genotypes and phenotypes of their children? 4. A type A woman whose father was type B marries a type B man whose mother was type A. What will be their childrens' possible genotypes and phenotypes? 5. What is the probability that a couple whose blood types are AB and O will have a type A child? 6. A couple has a child with type A blood. If one parent is type O, what are the possible genotypes of the other parent?
Crosses Involving Multiple Alleles
In previous activities, every gene was considered to have only two possible
alleles. For example, the alleles of the gene for plant height in peas are either
tall or short, and the alleles of the gene for fruit color in squash are either
yellow or white. However, there are genes for which more than two different
alleles exist. When this is the case the alleles are referred to as multiple alleles.
As you know, a diploid individual can carry only two alleles for any gene.
This is because for each gene one allele is carried on each of the two
chromosomes that constitute a pair of homologous chromosomes. But in a
population of individuals, more than two alleles of a gene can exist. For
example, one individual may have alleles 1 and 2 of a particular gene while
another individual may have alleles 2 and 5 of that same gene. The best known
example of multiple alleles involves the gene for blood type in humans. This
gene has three different alleles and is located on chromosome 9, two copies of
which exist in all human body cells. The alleles of this gene are designated as
follows:
I-codes for type A blood
18-codes for type B blood
i-codes for type O blood
I and 18 are each dominant over i, but are not dominant over each other. The
possible genotypes and corresponding blood types are as follows:
genotype phenotype (blood type)
ii
Step 2
|A|A
18₁
1818
|A|B
Step 3
O
SAMPLE PROBLEM
A woman with type A blood whose father was type O married a man with type AB blood. What will be the
possible genotypes and phenotypes of their children?
Step 1
A
A
B
B
AB
Determine the genotypes of the parents.
Type A woman with type O father i
Type AB man |A|B
IX AB
Determine the gamete genotypes produced by each parent.
Pii
|A|B|A,18
Set up a Punnett square using the gamete genotypes..
|A
18
Transcribed Image Text:Crosses Involving Multiple Alleles In previous activities, every gene was considered to have only two possible alleles. For example, the alleles of the gene for plant height in peas are either tall or short, and the alleles of the gene for fruit color in squash are either yellow or white. However, there are genes for which more than two different alleles exist. When this is the case the alleles are referred to as multiple alleles. As you know, a diploid individual can carry only two alleles for any gene. This is because for each gene one allele is carried on each of the two chromosomes that constitute a pair of homologous chromosomes. But in a population of individuals, more than two alleles of a gene can exist. For example, one individual may have alleles 1 and 2 of a particular gene while another individual may have alleles 2 and 5 of that same gene. The best known example of multiple alleles involves the gene for blood type in humans. This gene has three different alleles and is located on chromosome 9, two copies of which exist in all human body cells. The alleles of this gene are designated as follows: I-codes for type A blood 18-codes for type B blood i-codes for type O blood I and 18 are each dominant over i, but are not dominant over each other. The possible genotypes and corresponding blood types are as follows: genotype phenotype (blood type) ii Step 2 |A|A 18₁ 1818 |A|B Step 3 O SAMPLE PROBLEM A woman with type A blood whose father was type O married a man with type AB blood. What will be the possible genotypes and phenotypes of their children? Step 1 A A B B AB Determine the genotypes of the parents. Type A woman with type O father i Type AB man |A|B IX AB Determine the gamete genotypes produced by each parent. Pii |A|B|A,18 Set up a Punnett square using the gamete genotypes.. |A 18
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