Give a big-Oh characterization in terms of n, of the running time of the following code fragments Programming language: Java
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Give a big-Oh characterization in terms of n, of the running time of the
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- Implement the vacuum cleaning agent function in Python/Java for the scenario described below: Consider two-dimensional Boolean array of size m x n (m and n can each be equal to 4) where m is the number of rows, and n is the number of columns. Obtain numerical positive integer values for m and n as inputs from the user. Generate random numbers and scale them down to either a “0” or a “1” according to whether they represent “Clean” or “Dirty”, respectively. After filling the array with 0s or 1s, start at some random array position indicating the initial position of the vacuum cleaner. First check if at that current position, there is the presence of a “Dirt” or not determined by whether 0 or 1 is filled in at that initial position of the vacuum cleaner. If there is a “Dirt”, clean it, and if there is no “Dirt” do a No-operation. After this is done, generate random numbers modulo 4 to obtain random numbers 0, 1, 2, 3 indicating whether to take a left, right, up or down correspondingly. If…Write a recursive Java method that calculates the sum of n positive integer numbers. The math function is: f(n) = 1 + 2 + 3 + … + n. Jack, Peter and John were exploring a tunnel which allows only one person to pass through. Jack entered the tunnel first, followed by Peter. John entered the tunnel the last. The tunnel has a dead end. So the team has to turn back and retrieve from the tunnel one by one. Write a Java program based on a suitable data structure to simulate this process.JAVA Implement the equals method of the Arrow class. Two arrows are equal when they have the same starting point and direction. public class Arrow{ private Point start; private String direction; /** Constructs an arrow. @param x the x-position @param y the y-position @param direction a compass direction N E S W NE NW SE SW */ public Arrow(int x, int y, String direction) { start = new Point(); start.move(x, y); this.direction = direction; } /** Checks whether this arrow is equal to another. @param otherObject another arrow @return true if this arrow and otherObject have the same position and direction. */ public boolean equals(Object otherObject) { /* code goes here */ }}
- public class Soru2 { static void sort(char a[]) { for(int i = 0; i < a.length; i++) { for(int j = i + 1; j < a.length; j++) { if(a[j] == 'X' && a[i] == 'O') { char temp = a[j]; a[j]=a[i]; a[i]=temp; } } } for(int i = 0; i < a.length; i++) { System.out.print(a[i] + " "); } } public static void main(String[] args) { char a[] = {'X','O','X','O','X','O','X','O','X','O'}; sort(a); } } Calculate the time complexity and number of steps of the algorithm?JAVA In order to compute a power of two, you can take the next-lower power and double it. For example, if you want to compute 2^11 and you know that 2^10=1024, then 2^11=2×1024=2048. Write a recursive method public static int pow2(int n) where n is the exponent, that is based on this observation. If the exponent is negative, return -1. import java.util.Scanner; public class PowerTwo{ public static int pow2(int n) { /* code goes here */ } public static void main(String[] args) { Scanner in = new Scanner(System.in); while (in.hasNextInt()) { int exponent = in.nextInt(); System.out.println(pow2(exponent)); } }}For any element in keysList with a value smaller than 50, print the corresponding value in itemsList, followed by a space. Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 10 40 import java.util.Scanner; public class Compare { public static void main(String args[]) { final int SIZE_LIST = 4; int[] keysList = new int[SIZE_LIST]; int[] itemsList = new int[SIZE_LIST]; int i; Scanner input = new Scanner(System.in); keysList[0] = input.nextInt(); keysList[1] = input.nextInt(); keysList[2] = input.nextInt(); keysList[3] = input.nextInt(); itemsList[0] = input.nextInt(); itemsList[1] = input.nextInt(); itemsList[2] = input.nextInt(); itemsList[3] = input.nextInt(); //answer// System.out.println(); } }
- 2. In JAVA programming language write a program to input the elements of two integer arrays A1, A2 of size 10 and then print the absolute difference of the average of the arrays A1 and A2. The average of an array is the average of all the elements of the array.Java problem From the given array, create pairs of numbers from left to right, find the absolute value of the difference between each pair, find the minimum and maximum of the absolute values, and return it to a String array of size 1. Output format : {min_value : max_value} Sample input = {2,-1,4,7,2} Sample output={2:8}Write a recursive method called digitCount() that takes two integers, n and m as a parameter and returns the number of digits in n that are equal to m. Assume that n≥0 and 0≤m≤9 Ex: If the input is: 34443215 4 3 import java.util.Scanner; public class LabProgram { /* TODO: Write recursive digitCount() method here. */ public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int digits; int n= scnr.nextInt(); int m= scnr.nextInt(); digits = digitCount(n, m); System.out.println(digits); }}
- JAVA Question 2: For two integers m and n, their GCD (Greatest Common Divisor) can be computed by a recursive method. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Method body: If m is 0, the method returns n. If n is 0, the method returns m. If neither is 0, the method can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n (or m % n). The recursive method cannot have loops. Note: although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. main method: Prompt and read in two numbers to find the greatest common divisor. Call the gcd method with the two numbers as its argument. Print the result to the monitor. Example program run: Enter m: 12 Enter n: 28 GCD(12,28) = 4 And here is what I have so far, package CSCI1302;import java.util.*;public class RecursionDemo { public static void…Beginner Java import java.util.Arrays;import java.util.Scanner; Arrays and scanner required. Suppose that a Scanner object contains a bunch of tokens all on a single line separated by spaces. For example: 100.5 65 pizza 100 45.75 70 5.8 5 Also suppose that you have two integers n and m that are both positive. For example: n = 5 and m = 10 Write a static method: public static double partialSum(Scanner s, int n, int m) that takes a Scanner and two integers n and m as arguments and returns the sum of the integers read by the Scanner that are divisible by n and not divisible by m. In the above example, the integers divisible by 5 and not divisible by 10 are 65 and 5, so the result would be 70. If the Scanner is empty, or no tokens are valid integers, the result should be 0. You can assume the Scanner is not null. It is probably easiest to test your method by creating a Scanner with a String instead of System.in. The starter code for an example of how to do this is…I need help with this Java Problem as described in the image below: import java.util.Scanner; public class NumberPattern { // TODO: Write recursive printNumPattern() method public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int num1; int num2; num1 = scnr.nextInt(); num2 = scnr.nextInt(); printNumPattern(num1, num2); } }