see pic attached 10) Given a regular square pyramid Its base is a square whose side length is 16cm. Its lateral is anisosceles triangle whose leg is 17cm. If the angle between the base and the lateral is 0, find the valueof tane有一正四角錐、底面是邊長16cm 的正方形,側則面是腰長1"m 的等腰三角形,若底面與側面的夾角為e-則tan的值為何?有一正四角維,底面是邊長 16cm 的正方形,側面是腰長17cm的等腰三角形,若底面與側面的夾角為0,則tan 0的值為何?151(C)161(D)8.3,1915(A)(B)

Name: see pic attached 10) Given a regular square pyramid Its base is a squa
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: see pic attached 10) Given a regular square pyramid Its base is a square whose side length is 16cm. Its lateral is anisosceles triangle whose leg is 17cm. If the angle between the base and the lateral is 0, find the valueof tane有一正四角錐、底面是邊長16cm 的正方形,

Answered: Image /qna-images/answer/4f7a7f93-c094-4580-b6ff-6493c870f6fd.jpg

Math

Geometry

Given a regular square pyramid Its base is a square whose side length is 16cm. Its lateral is an isosceles triangle whose leg is 17cm. If the angle between the base and the lateral is O, find the value of tan6. 有一正四角錐、底面是邊長 16cm 的正方形,側面是腰長1"m 的等腰三角形,若底面與側面的夾角為日,則ian 的值為何? 有一正四角雞,底面是邊長16cm 的正方形,側面是腰長17cm的等腰三角形,若底面與側面的夾角為0,則tane 的值為何? 319 (B) 151 (C) 8. 161 15 (A) (D)

Given a regular square pyramid Its base is a square whose side length is 16cm. Its lateral is an isosceles triangle whose leg is 17cm. If the angle between the base and the lateral is O, find the value of tan6. 有一正四角錐、底面是邊長 16cm 的正方形,側面是腰長1"m 的等腰三角形,若底面與側面的夾角為日,則ian 的值為何? 有一正四角雞,底面是邊長16cm 的正方形,側面是腰長17cm的等腰三角形,若底面與側面的夾角為0,則tane 的值為何? 319 (B) 151 (C) 8. 161 15 (A) (D)

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter9: Surfaces And Solids

Section9.2: Pyramids, Area, And Volume

Problem 29E

See similar textbooks

Similar questions

a Is it really necessary to construct all three bisectors of the angles of a triangle to locate its incenter? b Is it really necessary to construct all three perpendicular bisectors of the sides of a triangle to locate its circumcenter?
Given that rectangle ABCE is similar to rectangle MNPR and that CDEPQR, what can you conclude regarding pentagon ABCDE and pentagon MNPQR?
a What is true of any pair of corresponding angles of two similar polygons? b What is true of any pairs of corresponding sides of two similar polygons?
A carpenter joins four boards of lengths 6 ft, 6 ft, 4 ft, and 4 ft, in that order, to form quadrilateral ABCD as shown. a What type of quadrilateral is formed? b How are angles B and D related?
A calendar is determined by using each of the 12 faces of a regular dodecahedron for one month of the year. With each side of the regular pentagonal face measuring 4cm, the area of each face is approximately 27.5 cm2. a What is the total surface area of the calendar? b If the material used to construct the calendar costs 0.8 of a cent per square centimeter, what is the cost of the materials used in construction?
The center of a circle of radius 2 inches is at a distance of 10 inches from the center of a circle of radius length 3 inches. To the nearest tenth of an inch, what is the approximate length of a common internal tangent? Use the hint provided in Exercise 38. HINT: use similar triangles to find OD and DP. Then apply the Pythagorean Theorem twice.
The center of a circle of radius 2 in. is at a distance of 10 in. from the center of a circle of radius length 3 in. To the nearest tenth of an inch, what is the approximate length of a common internal tangent? Use the hint provided in Exercise 38. HINT: use similar triangles to find OD and DP. Then apply the Pythagorean Theorem twice.
A satellite dish in the shape of a regular dodecagon 12 sides is nearly circular. Find: a mAB b mABC c mABC inscribed angle
The center of a circle of radius 3 inches is at a distance of 20 inches from the center of a circle of radius 9 inches. What is the exact length of common internal tangent AB? HINT: Use similar triangles to find OD and DP. Then apply the Pythagorean Theorem twice.