Please help! Given are five observations for two variables, and y.s² = MSE =Use the estimated regression equation: y = 65.7823 2.6591x.a. Compute the mean square error using equation.SSEn - 2(to 4 decimals)b. Compute the standard error of the estimate using equation.SSEn-2s = √MSE =- x)²(to 4 decimals)c. Compute the estimated standard deviation of b₁ using equation.SSb₁Xi -(to 4 decimals)d. Use the t-test to test the following hypotheses (α = 0.05):Ho: B1 = 0Ha: B1 0What is the p-value? Use Table 2 from Appendix B.p-value is - Select your answer -XiDegreesof FreedomYiCompute the value of the t-test statistic (Enter negative values as negative numbers).(to 3 decimals)Sum ofSquaresRegressionErrorTotalWhat is your conclusion, based on this F test?We - Select your answer - Ho.What is your conclusion?We - Select your answer - ✓ Ho.e. Use the F-test to test the hypotheses in part (d) at a 0.05 level of significance.Complete the F table below using Excel. Calculate the Sum of Squares (to 1 decimal), the Mean Squares (to 1 decimal), and the F ratio (to 2 decimals) and thep-value (to 4 decimals).Sourceof VariationMeanSquare2 7 12 15 2053 56 40 20 11Fp-value

As per the Bartleby guildlines we have to solve first three subparts.... Given that We have to find…

Answered: Given are five observations for two…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider a linear regression model for the decrease in blood pressure (mmHg) over a four-week period with muy=2.8+0.8x and standard deviation chi=3.2. The explanatory variable x is the number of servings fruits and vegetables in a calorie-controlled diet. Using the 68-95-99.7 rule, between what two values would approximately 95% of the observed responses, y, fall when x = 7?
In simple linear regression, at what value of the independent variable, X, will the 95% confidence interval for the average value of Y be narrowest? At what value will the 95% prediction interval for the value of Y for a sin gle new observation be narrowest?
The following estimated regression equation is based on 10 observations was presented. ŷ = 29.1270 + 0.5906x1 + 0.4980x2 . Here SST=6,724.125 , SSR = 6,216.375 , sb1 = 0.0813, sb2 = 0.0567. Compute MSR & MSE to 3 decimals, then compute F using the appropriate F test (round answer to 3 decimals). Use α = 0.05.
If Elliot collects data from a single sample and her dependent variable is assessed on a nominal scale, which of these difference tests would Elliot need to use to analyze her data? a. single sample t test b. between-subjects, one-way ANOVA. c. chi square goodness of fit test d. single-sample z test
Ten observations were provided for a dependent variable y and two independent variables x1 and x2; for these data, SST = 15,177.6 and SSR = 14,056.5. (a) Compute R2. (Round your answer to three decimal places.) R2 = (b)Compute Ra2.( Round your answer to three decimal places.) Ra2 = (c)Does the estimated regression equation explain a large amount of the variability in the data? Explain. (For purposes of this exercise, consider an amount large if it is at least 55%. Round your answer to one decimal place.) (Select Yes OR No) after adjusting for the number of independent variables in the model, we see that ______% of the variability in y has been accounted for.
Ten observations were provided for a dependent variable y and two independent variables x1 and x2; for these data, SST = 15,177.6 and SSR = 14,059.3. (a) Compute R2. (Round your answer to three decimal places.) R2 = (b) Compute Ra2. (Round your answer to three decimal places.) Ra2 = (c) Does the estimated regression equation explain a large amount of the variability in the data? Explain. (For purposes of this exercise, consider an amount large if it is at least 55%. Round your answer to one decimal place.) , after adjusting for the number of independent variables in the model, we see that % of the variability in y has been accounted for.
If Elliot collects data from a single sample and her dependent variable is assessed on a nominal scale, which of these difference tests would Elliot need to use to analyze her data? A. a single-sample t test B. a single-sample z test C. a between-subjects ANOVA D. a chi-square goodness-of-fit test
The following estimated regression equation based on 30 observations was presented. ŷ = 17.6 + 3.8x1 − 2.3x2 + 7.6x3 + 2.7x4 The values of SST and SSR are 1,807 and 1,757, respectively. (a) Compute R2. (Round your answer to three decimal places.) R2 = (b) Compute Ra2. (Round your answer to three decimal places.) Ra2 = (c) Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) The estimated regression equation did not provide a good fit as a large proportion of the variability in y has been explained by the estimated regression equation. The estimated regression equation provided a good fit as a large proportion of the variability in y has been explained by the estimated regression equation. The estimated regression equation provided a good fit as a small proportion of the variability in y has been explained by the estimated regression equation. The estimated regression equation did not provide a good…
Assume that variables xx and yy have a significant correlation, and that the line of best fit has been calculated as ˆy=1.4x+3.6y^=1.4x+3.6. One observation is (9,16.3)(9,16.3).What is the predicted value of yy for the value x=9x=9? What is the residual for the value x=9x=9? What is the best interpretation for the residual? The value 16.316.3 is below the average value for yy when x=9x=9 The value 99 is above the average value for yy when y=16.3y=16.3 The value 16.316.3 is above the average value for yy when x=9x=9. The value 16.316.3 is below the average value for xx when y=16.3
The following estimated regression equation based on 30 observations was presented. ŷ = 17.6 + 3.8x1 − 2.3x2 + 7.6x3 + 2.7x4 The values of SST and SSR are 1,801 and 1,758, respectively. (a)Compute R2. (Round your answer to three decimal places.) R2 = (b)Compute Ra2.(Round your answer to three decimal places.) Ra2 = (c) Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) The estimated regression equation provided a good fit as a small proportion of the variability in y has been explained by the estimated regression equation.The estimated regression equation did not provide a good fit as a large proportion of the variability in y has been explained by the estimated regression equation. The estimated regression equation did not provide a good fit as a small proportion of the variability in y has been explained by the estimated regression equation.The estimated regression equation provided a good fit as a…
The following estimated regression equation based on 10 observations was presented. ŷ = 29.1260 + 0.5306x1 + 0.4680x2 The values of SST and SSR are 6,728.125 and 6,215.375, respectively. (a) Find SSE. SSE = (b) Compute R2. (Round your answer to three decimal places.) R2 = (c) Compute Ra2. (Round your answer to three decimal places.) Ra2 = (d) Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) The estimated regression equation provided a good fit as a small proportion of the variability in y has been explained by the estimated regression equation.The estimated regression equation did not provide a good fit as a small proportion of the variability in y has been explained by the estimated regression equation. The estimated regression equation provided a good fit as a large proportion of the variability in y has been explained by the estimated regression equation.
In a sample of 12 randomly selected high school seniors, the mean score on a standardized test was 1200 and the standard deviation was 160.5. Further research suggests that the population mean score on this test for high school seniors is 1016. Does the t-value for the original sample fall between −t0.90 and t0.90? Assume that the population of test scores for high school seniors is normally distributed.

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