Given : Ba (AW = 137.327 g/cm³)%3DFCCAtomic radius = 0.235 nmQv = 1.23ev/atomT= 1125 °CDetermine: a) Number of lattice sites, N(atoms/m³)b) Number of vacancies,Nv (atoms/m3)Number of lattice sites, (N) =atoms/m3Number of vacancies, Nv =(atoms/m3)

Answered: Image /qna-images/answer/d0935942-2f3a-43fd-bd86-97ef535c4f24.jpg

Answered: Given : Ba (AW = 137.327 g/cm³) %3D FCC…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter11: Liquids And Solids

Section: Chapter Questions

Problem 11.81QE

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Given : Ba (AW = 137.327 g/cm³) %3D FCC Atomic radius = 0.235 nm Qv = 1.23ev/atom T= 1125 °C Determine: a) Number of lattice sites, N (atoms/m3) b) Number of vacancies, Nv (atoms/m3) Number of lattice sites, (N) = %3D atoms/m3 Number of vacancies, Nv = (atoms/m3)