Question
Asked Jul 7, 2019
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Given that a fluid at 260 degrees F has a kinematic viscosity of 145mm^2/s, determine its kinematic viscosity in SUS at 260 degrees F.

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Expert Answer

Step 1

Write the given temperature and its corresponding kinematic viscosity of the fluid.

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T 260 F v = 145 mm2/s

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Step 2

Write the expression for the SUS value of a fluid at any temperature “t”.

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SUS A(4.632v) (1) Here, A is constant and kinematic viscosity is V Write the equation for the factor "A" A (6.061x 105t)+0.994 (2)

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Step 3

Calculate the A factor and SUS using the ...

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Substitute 260°F for t in equation (2) A (6.061x 10x 260°F)0.994 -1.0098 Substitute 1.0098 for A and 145 mm/s for V in equation (1). SUS 1.0098(4.632 x 145) -678.194 SUS Thus, the equivalent viscosity of the fluid at 260°F is 678.194 SUS.

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Engineering

Mechanical Engineering

Fluid Mechanics

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