Basic Java Syntax (Practice 03)Introduction to Java Programming.-Explanation through with answers.-Without abbreviation make it clear writing.Thank you. Given the following Java code, choose the CORRECT statement from the below.String txt="Football";System.out.println(txt.toUpperCase());O String is a method, and toUpperCase() is a class.O String is a class, and toUpperCase() is a method.What is the output of the following Java code ?double d = -1* Math.round(-7.6);System.out.println("r="+(d+8));r=16.0r=1.0elser=-1.0r=0.0What is the output of the following Java code ?char ch = '#';if (!Character.isLetter(ch))System.out.println(++ch);System.out.println(--ch);ööö%

Here, we will discuss the correct answers and outputs of the given three Java programming questions.…

Given the following Java code, choose the CORRECT statement from the below. String txt="Football"; System.out.println(txt.toUpperCase()); String is a method, and toUpperCase() is a class. String is a class, and toUpperCase() is a method. What is the output of the following Java code ? double d = 1* Math.round(-7.6); System.out.println("r="+(d+8)); r=16.0 else r=1.0 Or=-1.0 r=0.0 What is the output of the following Java code ? char ch = '#'; if (!Character.isLetter(ch)) System.out.println(++ch); System.out.println(--ch); S %

Given the following Java code, choose the CORRECT statement from the below. String txt="Football"; System.out.println(txt.toUpperCase()); String is a method, and toUpperCase() is a class. String is a class, and toUpperCase() is a method. What is the output of the following Java code ? double d = 1* Math.round(-7.6); System.out.println("r="+(d+8)); r=16.0 else r=1.0 Or=-1.0 r=0.0 What is the output of the following Java code ? char ch = '#'; if (!Character.isLetter(ch)) System.out.println(++ch); System.out.println(--ch); S %

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter8: Advanced Method Concepts

Section: Chapter Questions

Problem 5E

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