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Given the following thermochemical equations:                    4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(l)    ∆Ho = -1531kJ                    N2O(g) + H2(g) → N2(g) + H2O (l)          ∆Ho = -367.4kJ                    H2(g) + ½O2(g) →H2O(l)                   ∆Ho = -285.9kJ Calculate the value of ∆Ho for the reaction 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(l)

Given the following thermochemical equations:                    4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(l)    ∆Ho = -1531kJ                    N2O(g) + H2(g) → N2(g) + H2O (l)          ∆Ho = -367.4kJ                    H2(g) + ½O2(g) →H2O(l)                   ∆Ho = -285.9kJ Calculate the value of ∆Ho for the reaction 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(l)

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 36QAP: Given the following thermochemical equations: 4B(s)+3O2(g)2B2O3(s)H=2543.8kJ H2(g)+12...
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Given the following thermochemical equations:

                   4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(l)    ∆Ho = -1531kJ

                   N2O(g) + H2(g) → N2(g) + H2O (l)          ∆Ho = -367.4kJ

                   H2(g) + ½O2(g) →H2O(l)                   ∆Ho = -285.9kJ

Calculate the value of ∆Ho for the reaction

2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(l)

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