Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react to form ammonia: N2(9) + 3 H2(g) → 2 NH3(g) AH =-92. kJ In the second step, ammonia and oxygen react to form nitric oxide and water: 4 NH3(9) + 50,(9) → 4 NO(9) + 6H,0(9) AH =-905. kJ Calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions. Round your answer to the nearest kJ. ?

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter2: Chemical Formulas, Equations, And Reaction Yields
Section: Chapter Questions
Problem 44AP: A possible practical way to eliminate oxides of nitrogen(such as NO2 ) from automobile exhaust gases...
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Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react to form ammonia:
N2(9) + 3 H2(9) 2 NH3(g)
AH=-92. kJ
dlo
In the second step, ammonia and oxygen react to form nitric oxide and water:
4 NH3(g) + 50,(9) → 4NO(g) + 6H,0(g)
AH=-905. kJ
Calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions.
Round your answer to the nearest kJ.
?
Transcribed Image Text:= 14 15 16 17 18 19 20 21 22 23 24 25 26 Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react to form ammonia: N2(9) + 3 H2(9) 2 NH3(g) AH=-92. kJ dlo In the second step, ammonia and oxygen react to form nitric oxide and water: 4 NH3(g) + 50,(9) → 4NO(g) + 6H,0(g) AH=-905. kJ Calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions. Round your answer to the nearest kJ. ?
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