Question 15Given the reaction:Cu2+ + Fe Cu + Fe2+The reaction is assumed to be that (Cu²+) =(Fe2+) = 1.0M and T = 298 K. As the reaction proceeds, Cu²+ =0.50 M while Fe2+ =1.50M. This occur after one minute.What is the EMF of the cell?What is the E of the cell after one minute?What is the Keq for this reaction?(Express in scientific notation, in this manner, ex. 1.25 x 10^+3All answers in 2 decimal places.Weak Oxidizing Agents/Strong Reducing AgentsStandard Reduction Potential Table (at 25°C, 101kPa, 1M)Half-ReactionLit+e → LiAl+3+3e → Alvolts-3.04-1.68-0.76Zn+2 +2e → ZnFe +2 +2e → Fe-0.442H₂O +2e → H₂ + 2OH--0.41Ni+2 +2e → Ni-0.26Pb+2 +2e → Pb-0.130.002H+ + 2e →→ H₂Cu+² +2e → Cu0.340.52Cu* + e → CuFe+3+eFe +20.77Ag* + e → Ag0.80O₂ + 4H2+4e2H₂O0.82Br₂ +2e →→2Br1.07Cl₂ +2e →→2C1-1.36Au +3+3e → Au1.52Strong Oxidizing Agents/Weak Reducing Agents

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Cu2+ + Fe Cu + Fe²+ The reaction is assumed to be that (Cu2+) =(Fe2+) =1.0M and T = 298 K. As the reaction proceeds, Cu²+ =0.50 M while Fe2+ =1.50M. This occur after one minute. What is the EMF of the cell? What is the E of the cell after one minute? What is the Keq for this reaction? (Express in scientific notation, in this manner, ex. 1.25 x 10^+3 All answers in 2 decimal places.

Cu2+ + Fe Cu + Fe²+ The reaction is assumed to be that (Cu2+) =(Fe2+) =1.0M and T = 298 K. As the reaction proceeds, Cu²+ =0.50 M while Fe2+ =1.50M. This occur after one minute. What is the EMF of the cell? What is the E of the cell after one minute? What is the Keq for this reaction? (Express in scientific notation, in this manner, ex. 1.25 x 10^+3 All answers in 2 decimal places.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter18: Electrochemistry

Section: Chapter Questions

Problem 148CP: You have a concentration cell with Cu electrodes and [Cu2+] = 1.00 M (right side) and 1.0 104M...

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