Given the standard enthalpy changes for the following two reactions: (1) 2Pb(s) + O₂(g) → 2PbO(s) ΔΗ° = - 434.6 kJ (2) Pb(s) + Cl₂(g) → PbCl₂ (s) ΔΗ° = -359.4 kJ what is the standard enthalpy change for the reaction: (3) 2PbCl₂ (s) + O₂(g) → 2PbO(s) + 2Cl2 (g) AH° = ? ΔΗ° = kJ

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.27QE
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Given the standard enthalpy changes for the following two reactions:
(1) 2Pb(s) + O₂(g) → 2PbO(s)
ΔΗ°
(2) Pb(s) + Cl₂(g) → PbCl₂ (s)
ΔΗ°
ΔΗ°
what is the standard enthalpy change for the reaction:
(3) 2PbCl₂ (s) + O2 (g) → 2PbO(s) + 2Cl₂(g)
ΔΗ° =?
=
= 434.6 kJ
- 359.4 kJ
KJ
=
Transcribed Image Text:Given the standard enthalpy changes for the following two reactions: (1) 2Pb(s) + O₂(g) → 2PbO(s) ΔΗ° (2) Pb(s) + Cl₂(g) → PbCl₂ (s) ΔΗ° ΔΗ° what is the standard enthalpy change for the reaction: (3) 2PbCl₂ (s) + O2 (g) → 2PbO(s) + 2Cl₂(g) ΔΗ° =? = = 434.6 kJ - 359.4 kJ KJ =
Expert Solution
Step 1

 

Recall the given reactions,                          1 2 Pb s  +  O2 g    2 PbO s                         H° = - 434.6 KJ                          2 Pb s  +  Cl2 g    PbCl2 s                            H° = - 359.4 KJWe have to calculate the standard enthalpy change for the reaction :                         3 2 PbCl2 s  +  O2 g    2 PbO s  +  2 Cl2 g               H° = ?

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