22.Below are the reaction steps in a certain polymerization process,which may occur by either an uncatalyzed or an acid-catalyzedpathway.0–Hki- R-C+k2R--С-о—н+ HAA-0–HGroup 10–H0–Hk3R-Ċ+A--0–HR-Ć-0–Hk40–HR-ó+A-Group 2H0–H||-C-0–R'R-ksR–C-0¬H+ Hо + НАR-ó+AGroup 323.Given these data for the acid-catalyzed reaction in question 22, findthe rate law.(RCOOH], M[R’OH], M[HA], MInitial Rate, M-min0.350.350.504.600.620.350.508.140.350.810.5010.60.350.500.759.84Rate =k[RCOOH][R'OH]Rate =k[RCOOH][R'OH][HA]Rate =k[RCOOR']/{[RCOOH][R'OH]}Rate =k[R'OH]Rate = k[RCOOH]

Answered: Image /qna-images/answer/a9e23d2e-3608-465b-8b32-37d847967a4c.jpg

Given these data for the acid-catalyzed reaction in question 22, find the rate law. (RCOOH], M (R’OH], M (HA], M Initial Rate, M•min"' 0.35 0.35 0.50 4.60 0.62 0.35 0.50 8.14 0.35 0.81 0.50 10.6 0.35 0.50 0.75 9.84 Rate = k[RCOOH][R'OH] Rate = k[RCOOH][R'OH][HA] Rate = k[RCOOR']/{[RCOOH][R'OH]} Rate = k[R'OH] Rate = k[RCOOH] oo00 o

Given these data for the acid-catalyzed reaction in question 22, find the rate law. (RCOOH], M (R’OH], M (HA], M Initial Rate, M•min"' 0.35 0.35 0.50 4.60 0.62 0.35 0.50 8.14 0.35 0.81 0.50 10.6 0.35 0.50 0.75 9.84 Rate = k[RCOOH][R'OH] Rate = k[RCOOH][R'OH][HA] Rate = k[RCOOR']/{[RCOOH][R'OH]} Rate = k[R'OH] Rate = k[RCOOH] oo00 o

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter31: Synthetic Polymers

Section31.SE: Something Extra

Problem 21AP

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