Given two integer arrays prevValues and newValues. Which code copies the array prevValues into newValues? The size of both arrays is NUM_ELEMENTS. newvalues = prevvalues; newvalues[] - prevvalues[]; newvalues [NUM_ELEMENTS] = prevvalues [NUM_ELEMENTS]; for (i = 0; i < NUM_ELEMENTS; ++i) { newvals[i] = prevvals[1];

Given two integer arrays prevValues and newValues. Which code copies the array prevValues into newValues? The size of both arrays is NUM_ELEMENTS. newvalues = prevvalues; newvalues[] - prevvalues[]; newvalues [NUM_ELEMENTS] = prevvalues [NUM_ELEMENTS]; for (i = 0; i < NUM_ELEMENTS; ++i) { newvals[i] = prevvals[1];

Programming Logic & Design Comprehensive

9th Edition

ISBN:9781337669405

Author:FARRELL

Publisher:FARRELL

Chapter6: Arrays

Section: Chapter Questions

Problem 17RQ

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Given two integer arrays prevValues and newValues. Which code copies the array prevValues into newValues? The size of both arrays is NUM_ELEMENTS. a. newValues = prevValues; b. newValues[] = prevValues[]; c. newValues[NUM_ELEMENTS] = prevValues[NUM_ELEMENTS]; d. <code>for (i = 0; i < NUM_ELEMENTS; ++i) { newValues[i] = prevValues[i]; }</code> JAVA
given an array of integer values , return true if 6 appears as either the first or last element in the array. firstLast6([1,2,36]) true firstLast([6,1,2,3]) true firstLast([13,6,1,2,3]) false
/*Code: Construct BST From Sorted ArraySend FeedbackGiven a sorted integer array A of size n, which contains all unique elements. You need to construct a balanced BST from this input array. Return the root of constructed BST.Note: If array size is even, take first mid as root.Input format:The first line of input contains an integer, which denotes the value of n. The following line contains n space separated integers, that denote the values of array.Output Format:The first and only line of output contains values of BST nodes, printed in pre order traversal.Constraints:Time Limit: 1 secondSample Input 1:71 2 3 4 5 6 7Sample Output 1:4 2 1 3 6 5 7 */public class SortedArrayToBst { /* Binary Tree Node class * * class BinaryTreeNode<T> { T data; BinaryTreeNode<T> left; BinaryTreeNode<T> right; public BinaryTreeNode(T data) { this.data = data; } } */…
If A is a circular array of MAX elements, and rear is an index into that array, what is the formula for the index after rear? a. (rear % 1) + MAX b. rear + (1 % MAX) c. rear % (1 + MAX) d. (rear + 1) % MAX
An array having a character subscript can be indexed using a computer language, as in CHR_ARRAY['A':'D']. In this scenario, the characters' ordinal numbers (ORDs), such as ORD('A') = 1, ORD('B') = 2, ORD('Z') = 26 and so on, are used to designate the array's elements, CHR_ARRAY['A'], CHR_ARRAY['B'], and so on. Beginning at position 500, two arrays called TEMP[1:5, -1:2] and CODE['A':'Z', 1:2] are now kept in the RAM. Furthermore, CODE outperforms TEMP in storage. Determine the locations of the following addresses: (i) TEMP[5, -1], (ii) CODE['N',2], and (iii) CODE['Z',1].
Consider the following code: .dataarray word 1, 2, 3, 4, 5.codemov eax, offset arraymov ecx, lengthof arrayloopstart:add byte ptr [eax], 1add eax, 2loop loopstart What are the values in the array after this code is finished executing?
Parameters array - Any JavaScript Array size - A positive integer Number indicating the desired "chunk" size. Return Value A new Array of Arrays. Each sub-Array has a length equal to size. Remaining elements are gathered into a final sub-Array. Do not mutate the input array Do not use Array.prototype.slice in your implementation.Do not use Array.prototype.shift in your implementation.Do not use Array.prototype.pop in your implementation.Do not use Array.prototype.splice in your implementation. Please fix this JavaScript function so that the when calling the function with the parameters chunk([false, true, false, true], 3); the output is [[false, true, false], [true]] (subarrays)and when the parameters are chunk([undefined, null, 0, false, NaN, ""], 3); the output is [[undefined, null, 0], [false, NaN, ""]] thank you very much! function chunk(ar, sz) { var res = []; var ind = 0; // itterating through the new length of resulting array for (var i = 0; i < ar.length / sz; i++)…
Given an array, find the next greater element for each element in the array, ifavailable. If not available, print the element itself. The next greater element y for anelement x in the array is the first element that is greater than x and occurs on its rightside. The next greater element of the right most element in an array is the elementitself.Example: Given A = [ 6 8 4 3 9] the next greater element listB = [8 9 9 9 9]
in java Integer numElements is read from input, representing the number of integers to be read next. Then, the remaining integers are read and stored into array valuesArray. For each element in valuesArray that is divisible by 9, assign the element with the element's current value plus 1. Ex: If the input is: 3 81 99 30 then the output is: Original values: 81 99 30 New values: 82 100 30 Note: (x % 9 == 0) returns true if x is divisible by 9. 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 for (i=0; i<valuesArray.length; ++i) { valuesArray[i] =scnr.nextInt(); } System.out.print("Original values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); /* Your code goes here */ System.out.print("New values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); } }
An_array and a number kFind the max elements of each of its sub-arrays of length k. Keep indexes of good candidates in deque d.The indexes in d are from the current window, they're increasing,and their corresponding nums are decreasing.Then the first deque element is the index of the largest window value. For each index i: 1. Pop (from the end) indexes of smaller elements (they'll be useless).2. Append the current index.3. Pop (from the front) the index i - k, if it's still in the deque (it falls out of the window).4. If our window has reached size k, append the current window maximum to the output..
If an array is given, identify the next bigger element for each element in the array, if one exists. If the element is not accessible, print the element itself. The next bigger element y in the array for an element x is the first element that is greater than x and appears on its right side. The element itself is the next bigger member of the array's rightmost element.For instance, if A = [6 8 4 3 9], the next bigger element list B = [8 9 9 9 9].
Write a program to ask the user for the number of arrays he wants to maintain and then populate eacharray by taking elements from the user. Merge all these arrays in another array and finally remove duplicateelements from the merged array.