G(lodobenzene) = 66 kJ/mol; %3! G(Benzenediazonium chloride) = -302 kJ/mol: %3D G(Hydrogen Chloride) = -44 kJ/mol: G(Boron trifluoride) = 373 kJ/mol:

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.95QE: Suppose you have an exothermic reaction with H = 15 kJ and a S of +150 J/K. Calculate G and Keq at...
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Question 20
Calculate the standard change in Gibbs free ener he following reaction:
N,CI
+ HBF, -
+ N, + BF, + HCI
Assume that:
AG(lodobenzene) = 66 kJ/mol:
AG(Benzenediazonium chloride) = -302 kJ/mol:
AG(Hydrogen Chloride) = -44 kJ/mol:
AG(Boron trifluoride) = 373 kJ/mol:
AG(Nitrogen gas) = -196 kJ/mol:
AG(Fluoroboric acid) = -256 kJ/mol.
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Transcribed Image Text:Question 20 Calculate the standard change in Gibbs free ener he following reaction: N,CI + HBF, - + N, + BF, + HCI Assume that: AG(lodobenzene) = 66 kJ/mol: AG(Benzenediazonium chloride) = -302 kJ/mol: AG(Hydrogen Chloride) = -44 kJ/mol: AG(Boron trifluoride) = 373 kJ/mol: AG(Nitrogen gas) = -196 kJ/mol: AG(Fluoroboric acid) = -256 kJ/mol. • Previous Next» earch W
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