Match each reaction with its standard free‑energy change. Glucose + ATP →→ glucose 6-phosphate + ADPGlucose 6-phosphate fructose 6-phosphateFructose 6-phosphate + ATP → fructose 1,6-bisphosphateFructose 1,6-bisphosphate dihydroxyacetone phosphate + glyceraldehyde 3-phosphateDihydroxyacetone phosphate glyceraldehyde 3-phosphateAG'° = 7.5 kJ/molAG'° -16.7 kJ/molAG'° =Answer BankAG'° = 1.7 kJ/molAG'° -14.2 kJ/molWhat is the net standard free-energy change of the preparatory phase of glycolysis?AG'° = 23.8 kJ/molkJ/mol

Glycolysis is a process of conversion of glucose into 2 molecules of pyruvate. The preparatory…

Answered: Glucose + ATP →→ glucose 6-phosphate +…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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In which of the following metabolic conversions is ATP “generated” during glycolysis? Glucose —> Glucose-6-phosphate 1,3-Bisphosphoglycerate —> 3-Phosphoglycerate Fructose-1,6-bisphosphate —> Dihydroxyacetone phosphate + Glyceraldehyde-3-phosphate Glucose-6-phosphate —> Fructose-6-phosphate 2-Phosphoglycerate —> 3-Phosphoglycerate
Which of the following are examples of structural isomers formed during metabolsim? Select one: a. 3-phosphoglycerate to 2-phosphoglycerate b. Dihydroxyacetone and glyceraldehyde-3-phosphate c. glucose-6-phosphate converted to fructose-6-phosphate d. citrate converted to isocitrate e. All of these are examples of structural isomers.
Consider the following chemical reaction: Glucose + ATP → Glucose-6-Phosphate + ADP + Pi Given the following information, calculate the actual free energy change (G’) of this reaction. G’ of Glucose + ATP → Glucose-6-Phosphate + ADP + Pi = -16.7 kJ/mol [Glucose] = 5.0 mM [ATP] = 1.85 mM [Glucose-6-Phosphate] = 0.083 mM [ADP] = 0.14 mM [Pi] = 1.0 mM Temperature = 37 C R (Gas Constant) = 8.314 J/mol•K
The ΔG°′ value for glucose-1-phosphate is -20.9 kJ/mol. If glucose and phosphate are both at 4.8 mM, what is the equilibrium concentration of glucose-1-phosphate?
Classify each of the following sugar pairs as enantiomers, diastereomers, epimers, or an aldose–ketose pair. a. D-erythrose and D-threose b. D-glucose and D-mannose c. D-ribose and L-ribose d. D-allose and D-galactose e. D-glyceraldehyde and dihydroxyacetone
What two 3-carbon molecules are generated by the cleavage of fructose-1,6-bisphosphate?A) glyceraldehyde-3-phosphate and 3-phosphoglycerateB) glyceraldehyde-3-phosphate and dihydroxyacetone phosphateC) pyruvate and phosphoenolpyruvateD) enolase and 2-phosphoglycerateE) glyceraldehyde-3-phosphate and pyruvate
Consider the following reaction: Glucose-1-phosphate → Glucose-6-phosphate ΔG° = −7.1 kJ/mol What is the equilibrium constant for this reaction at 25oC?
If the DGo for ATP hydrolysis into ADP + inorganic phosphate is -7.3 kcal/mole, and the DGo for sucrose synthesis from glucose + fructose is +5.5 kcal/mole, calculate standard free energy change for the combined reaction of ATP + glucose + fructose g ADP + sucrose + inorganic phosphate. DGo = -12.8 kcal/mole DGo = -1.8 kcal/mole DGo = 0 kcal/mole DGo = +1.8 kcal/mole DGo = +12.8 kcal/mole
The free energy of hydrolysis of an α(1→4) glycosidic bond is −15.5 kJ ⋅mol−1, whereas that of an α(1→6) glycosidic bond is −7.1 kJ ⋅ mol−1. Use these data to explain why glycogen debranching includes three reactions [breaking and re-forming α(1→4) bonds and hydrolyzing α(1→6) bonds], whereas glycogen branching requires only two reactions [breaking α(1→4) bonds and forming α(1→6) bonds].
The glycolytic enzyme aldolase catalyzes the following cleavage reaction: Fructose 1,6-bisphosphate ↔ glyceraldehyde-3-phosphate + dihydroxyacetone phosphate Here is information on the concentrations of these compounds in hepatocytes (liver cells). Reactant Concentration (M) Fructose 1,6-bisphosphate 1.4 x 10-5 glyceraldehyde-3-phosphate 3 x 10-6 dihydroxyacetone phosphate 1.6 x 10-5 The standard transformed free energy change (ΔG'°) of the reaction is +23.8 kJ/mol. At body temperature (37oC), is the reaction exergonic or endergonic in the hepatocyte? What is the value of the actual free energy change (ΔG) in the cell?
How many NTP molecules are required to synthesize glucose from each of the following compounds? (a) Glucose 6-phosphate (b) Fructose 1,6-bisphosphate (c) Two molecules of oxaloacetate (d) Two molecules of dihydroxyacetone phosphate
Consider the following list of phosphorylated compounds with their free energy changes of phosphate hydrolysis: Glucose-1-phosphate (-5.0 kcal/mol), PEP (-14.8 kcal/mole), 1,3-bisphosphoglycerate (-11.8 kcal/mole) and Glucose-6-Phosphate (-3.3 kcal/mol). Given that the free energy change of ATP hydrolysis is -7.3 kcal/mole, which of these molecules be directly synthesized by the transfer of a phospho- group from ATP? 1,3-bisphosphoglycerate Glucose-6-phosphate All of those phosphorylated compounds. PEP Glucose-1-phosphate

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