greater O less O equal

Q: A 6.00-kg object is attached to one end of a horizontal spring that has a negligible mass and a…

A: Given Mass of object = 6.0 kg Spring constant = 300 N/m Compression in spring given = 10 cm from the…

Q: A block of mass m = 2.8 kg is dropped (starting from rest) from a height h = 0.81 meters above the…

A: Consider the top of the spring as the reference line. Apply principle of conservation of energy…

Q: A 1500-kg car moving at 25 m/s hits an initially uncompressed horizontal spring with spring constant…

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Q: A 2.90-kg block is released from rest and allowed to slide down a frictionless surface and into a…

A: Mass of box=2.9kg Spring constant=463N/m Height=0.5m

Q: A 2 kg-block (ml) is moving on a frictionless flat table with a 10 m/s speed. The other block, with…

A: Due to the spring attached at the back of the second block, the collision will not elastic but…

Q: A vertical spring with elastic constant 95 N/m is compressed by 25 cm, and an object of mass 350 g…

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Q: A weight of 40N is placed on a horizontal plane touching one end of a horizontal spring whose other…

A: Given spring constant k= 5N/mm=5000N/m Weight of block =40N this gives mass m of block =4.08kg ~4 kg…

Q: A spring with a spring constant of 335 N/m is initially compressed by a distance of 0.045 m from its…

A: Given data: k = 335 N/m x= 0.045 m m=0.045 kg Need to determine the speed of the block.

Q: A 690 gram block is released from a height h0 above the top of an ideal spring of spring constant…

A: mass of block (m) = 690 gram or m = 0.69 kg spring constant (k) = 400 N/m  compression in spring (x)…

Q: A 2-kg block on a rough horizontal surface is attached to spring (k = 800 N/m); the other end of the…

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Q: a box of mass  m = 9.20 kg is sliding across a horizontal frictionless surface with an initial speed…

A: According to the law of conservation of energy , energy can neither be created nor destroyed but can…

Q: A vertical spring with a spring constant of 450 N/m is mounted on the floor. From directly above the…

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Q: A spring of negligible mass stretches 3.46 cm from its relaxed length when a force of 5.40 N is…

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Q: An inclined plane of angle e=20° has a spring of force constant k=500 N/m fastened securely at the…

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Q: A block of mass (m=2.00kg) is attached to a spring of force constant k=4.05x10^2 N/m that lies on a…

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Q: A box is pressed against a horizontal spring, compressing the spring from its relaxed length. The…

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Q: A spring with a constant of 730 N/m is compressed by a block of mass m = 1.2 kg. When the block is…

A: m = 1.2 kg k = 730 N/m L = 0.05 m coefficient of kinetic friction = 0.44 v = 2.3 m/s Using equation…

Q: An ideal spring is used to stop blocks as they slide along a table without friction. A 0.80 kg block…

A: Given: mass of the block (m) = 0.80 kg                                         speed (v) = 1.6 m/s…

Q: A block of mass 1.6 kg is held against a horizontal spring so that the spring is compressed 17 cm.…

A: The normal reaction acting on the block is: Therefore, the frictional force acting on the block is:…

Q: A 1.68 kg block is held in place against the spring by a 39 NN horizontal external force. The…

A: Since the surface up to B is frictionless till the point B block moves with a velocity 2.1 m/s.Then…

Q: A vertical spring with a spring constant of 480 N/m is mounted on the floor. From directly above the…

A: The spring constant of the spring = 480 N/m.The mass of the block =0.30 kg.The compressed distance =…

Q: A block of mass 2 kg is attached to the end of a spring of force constant 180 kN/m as in fig. (a).…

A: Given data The mass of the block is m=2 kg The spring constant is K=180 kN/m The amplitude of the…

Q: An m = 20.0 g object is held against the free end of a spring of constant k = 25.0 N/m that is…

A: Frictional force is given by the formula f=μN, where μ is coefficient of friction and N is normal…

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 4.95 x 102 N/m that lies…

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Q: As shown in the figure below, a box of mass m = 9.80 kg is sliding across a horizontal…

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Q: A block is suspended from a vertical spring which causes it to stretch by 10.0cm from its…

A: The elastic potential energy of the spring is, U=12kx2k=2Ux2 Substitute the values, to find the…

Q: A bungee jumper steps off a bridge with zero initial velocity and falls straight down towards the…

A: The energy stored in the spring is given by  U = 0.5 ky2 where, k is the spring constant and y is…

Q: a box of mass  m = 9.20 kg  is sliding across a horizontal frictionless surface with an initial…

A: (given)              Mass of box = 9.20 kg              Initial speed = 2.80 kg Spring constant ( k…

Q: A horizontal spring has a spring constant of 31.5 N/m. A mass of 4k g is attached to the  spring and…

A: Given: The mass of the object is 4 kg. The spring constant is 31.5 N/m. The amplitude of the system…

Q: A 0.250-kg block resting on a frictionless, horizon- tal surface is attached to a spring whose force…

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Q: A system contains a perfectly elastic spring, with an unstretched length of 20 cm and a spring…

A: When a spring is stretched, elastic potential energy gets stored inside it which is given by,…

Q: A spring-powered dart gun is unstretched and has a spring constant 16.0 N/m. The spring is…

A: Data Given,  Spring constant ( k ) = 16 N/m Extension of the Spring  ( x ) = 8 cm             = 0.08…

Q: An m = 20.0 g object is held against the free end of a d, spring of constant k = 25.0 N/m that is…

A: Given data The mass of the object is: m = 20 g The value of the spring constant is:  k = 25 N/m The…

Q: The 8-kg block is moving with an initial speed of 8 m/s. If the coefficient of kinetic friction…

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Q: As shown in the figure, a 1.50-kg box is held at rest against a spring with a force constant k = 790…

A: Given that the value of of mass of the box and force constant and coefficient of kinetic friction…

Q: An object of mass 1.25 kg at the bottom of a ramp is given an initial speed of 4.45 m/s up the 30.0°…

A: m=1.25 kgθ=300K=Spring ConstantV1=Initial Velocity=4.45 m/sV2=Final Velocity =0μ=0.250s1=1+0.350…

Q: A block of mass 0.5 kg on a horizontal surface is attached to a horizontal spring of negligible mass…

A: calculation

Q: As shown in the figure below, a box of mass m = 5.80 kg is sliding across a horizontal frictionless…

A: At the moment the spring was fully compressed, the box comes to momentary at rest. At this point,…

Q: A box is pressed against a horizontal spring, compressing the spring from its relaxed length. The…

A: Solution: (1)  Maximum height attained by the box is only depends on angle of projection and initial…

Q: A bullet with mass 4.95 g is fired horizontally into a 1.972-kg block attached to a horizontal…

A: Given information: The mass of the bullet (m1) = 4.95 g = 0.00495 kg The mass of the block (m2) =…

Q: Q: A 1.00-kg block is moving at vo = 10 m/s along a frictionless, horizontal surface toward a spring…

A: Given: m= 1kg vo=10 m/s k=100 N/m let maximum compression in the spring= x Use conservation of total…

Q: A 7.2-kg mass is hanging from the ceiling of an elevator by a spring with spring constant k = 150N/m…

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Q: A mass of 0.8 kg is attached to a horizontal spring whose stiffness is 10 N/m. Friction is…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.