gth of magnitude 40.0 cm. (b) Both lenses are diverging lenses having focal lengths of the magnitudes as in the problem in exercise 1.1. NOTE: The final answer should be: (a) I1=200cm; (b) s'2=-37.5cm; y'2=−1.80cm; (c) The final image is s'=37.5cm to the left of the second lens, y'=1.80cm, inverted. EXERCISE 1.1 (for reference) A 1.20cm tall object is 50.0cm to the left of a converging lens

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter26: Image Formation By Mirrors And Lenses
Section: Chapter Questions
Problem 63P
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EXERCISE 1.2 SOLVE:

Repeat the problem in exercise 1.1 using the same lenses except for the following changes:
(a) The first lens is a diverging lens having a focal length of magnitude 40.0 cm.
(b) Both lenses are diverging lenses having focal lengths of the magnitudes as in the problem in exercise 1.1.

NOTE: The final answer should be:

(a) I1=200cm; (b) s'2=-37.5cm; y'2=−1.80cm; (c) The final image is s'=37.5cm to the left of the second lens, y'=1.80cm, inverted.

EXERCISE 1.1 (for reference)

A 1.20cm tall object is 50.0cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one has a focal length of 60.0cm, is located 300.0cm to the right of the first lens along the same optic axis.
(a) Find the location and height of the image (call it I1) formed by the lens with a focal length of 40.0cm.
(b) I1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.

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