Give a clear handwritten answer with explanation...please give answer all sub parts with explanation Cowen(A) 2HBJ (g) = H₂ cg)+85₂ cg)(9)ke[2HBO][H₂JB8₂](11) kc = [H₂2₂ JB 8₂][HBO]²(1) kc = [HBO]2[H₂] [B√₂](B) SF₂ (g) + C1₂ (9) = 2 cl Fg (3(9)(i) ke = [CIF3](ii) keCRJEC12][CIFS]²[F-₂ J5 (C1₂](²²) ke = [F₂]³ [Cl2][elfs ]²(e) CH4 (9) + C1₂ (8) =CH₂Cl (8)+Heleg](i) kc = [HCl ][CH3C1]сскажени)(ii)Kc = [C12₂] [CHU][Hel] [CH3C1]2(ii) kc = (C3] [2]CCH₂) (CH3C1)(0) B1₂ (91+ Cl₂ (g) = 2 Breleg)(1) kcCB₂ [1₂]2[BrctJ2=(11) ke= [Bret] ²[B8₂] [C1₂](iii) ke = [2 Brd][Br₂][C1₂]

Answered: Image /qna-images/answer/85b7debe-a8c6-4e45-840b-ceed6fc9b1ae.jpg

Gwen (а) 2нва сд) = На ед) + бог сд) (1) ke что Кс (ii) ke ke = (B) sFz cg'tch2 c9) = 2CFg (3) (;) Кс = [cifЗЈ (ii) Санвој CH2 ХВО2) [H₂JB8₂] Снвој2 - Сн во ]2 CH2 ] [ВБ2] = СЂЈССЂ2] [CIFS]² [F2 Sack) (ii) ke= CF2J5 [ск2] Calfs 32 (e) CH₂ (9) + C1₂ (8) =CH₂Cl (8)+Heleg) сни (i) kc = [HCl ][CH3C1] сскажени) кс =(12) [ениј [Hel] [CH3C1] (4) кс = (снасiзд секо сена Сенза) 9) ва2 с917 сhед 2 врсіеg) Вог Cl2 Brci свог ЈСС12] (т) кс [Bret² (11) kez [Bret] 2 свог Ј СС12] (iii) ke = [2 Вас [Вого ССЂУ

Gwen (а) 2нва сд) = На ед) + бог сд) (1) ke что Кс (ii) ke ke = (B) sFz cg'tch2 c9) = 2CFg (3) (;) Кс = [cifЗЈ (ii) Санвој CH2 ХВО2) [H₂JB8₂] Снвој2 - Сн во ]2 CH2 ] [ВБ2] = СЂЈССЂ2] [CIFS]² [F2 Sack) (ii) ke= CF2J5 [ск2] Calfs 32 (e) CH₂ (9) + C1₂ (8) =CH₂Cl (8)+Heleg) сни (i) kc = [HCl ][CH3C1] сскажени) кс =(12) [ениј [Hel] [CH3C1] (4) кс = (снасiзд секо сена Сенза) 9) ва2 с917 сhед 2 врсіеg) Вог Cl2 Brci свог ЈСС12] (т) кс [Bret² (11) kez [Bret] 2 свог Ј СС12] (iii) ke = [2 Вас [Вого ССЂУ

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.12QAP

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