In the quadruplicate titration of 0.2068 g; 0.1997g; 0.2245 g and 0.2137 g of sodium carbonate 36.31 mL were spent; 35.11mL; 39.00 mL and 37.54 mL of perchloric acid. a) Calculate the average molarity of the perchloric acid solution. b) Would there be statistical justification for rejecting the furthest molarity? Tabular Q = 0.829 for n = 4 and 95% confidence.

In the quadruplicate titration of 0.2068 g; 0.1997g; 0.2245 g and 0.2137 g of sodium carbonate 36.31 mL were spent; 35.11mL; 39.00 mL and 37.54 mL of perchloric acid. a) Calculate the average molarity of the perchloric acid solution. b) Would there be statistical justification for rejecting the furthest molarity? Tabular Q = 0.829 for n = 4 and 95% confidence.

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter16: Reactions Between Acids And Bases

Section: Chapter Questions

Problem 16.54QE

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Na2CO3 served as the primary standard in a titration experiment. Find the molarity of the titrant given the following data in 3 decimal places. Show solutions Primary Standard Used: Na2CO3Formula Mass of 1º standard: 105.99 g/mol% purity of 1º standard: 95% Trial 1 2 3 1º Standard weight, g 0.1005 0.1001 0.0997 Net volume of HCl, mL 9.30 9.00 8.90 Molarity of HCl X1 X2 X3
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If 1.000ml of a solution of KMnO4 is equivalent to 0.1000mmol of sodium formate (HCO2Na) in the following titration: 2HCO2-+ 2MnO4-+ H2O → 3CO2 + 2MnO2 + 5OH-, what is the value of the KMnO4 in terms of grams of CaO in the volumetric method for calcium in which that element is precipitated as CaC2O4•H2O, the precipitate filtered and dissolved in dilute H2SO4, and the oxalate titrated with permanganate?
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