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Can you help me part H? Which is the formula of this rule of reaction?
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- Calculate the ΔG°rxn using the following information. 2 H2S(g) + 3 O2(g) → 2 SO2(g) + 2 H2O(g) ΔG°rxn = ? ΔG°f (kJ/mol) -33.4 -300.1 -228.6 Group of answer choices +990.6 kJ -1124 kJ +562.1 kJ +72.0 kJ -990.6 kJOrgonic Chemistry II: The answer is writtten as followed. But I Need Explanation. My question is that: Can I siwtch reagent 2 to reagent 1? for example reagent 1 is Cl2,Fecl3, can I changed it to reagent 2??? Why and why not???Find the deltaH for the reaction below, given the following reactions and subsequent deltaH values: N2H4(l) + H2(g) —> 2NH3 (g) N2H4(l) + CH4O(l) —> CH2O (g) + N2(g) + 3H2(g)—— deltaH= -32.8kj N2(g)+ 3H2(g) —> 2NH3 (g)—deltaH=-57.2 kj CH4O(l) —>CH2O(g) + H2(g) —-deltaH= -65 kj SIG FIGS
- Compound ΔHf (kj/mol) C2H5OH(i) -277.6 H2O(i) -285.8 H2O(g) -241.8 CO2(g) -393.5 CO(g) -110.5 H2O2(i) -187.6 C3H8(g) -103.8 What is the ΔH for the following reaction? C2H5OH(i) + 3O2 (g) --> 2CO2(g) + 3H2O(i)In which species (NO3- or CH3NO2) are the N-Obond(s) longer? In which species (NO3- or CH3NO2) are the N-Obond(s) weaker?Please help me I don't understand this, its a simple mecahnism but im lost.
- Answer Q35, 34 showing detailly all explanationsCalculate ∆Hrxn for the following reaction:N2H4(l) + CH4O(l) → CH2O(g) + N2(g) + 3H2(g)Use the following reactions and given ∆H values.2 NH3(g) → N2H4(l) + H2(g) ΔH = +22.5 kJ/molN2(g) + 3 H 2(g) → 2 NH3(g) ΔH = +57.5 kJ/molCH2O(g) + H2(g) → CH4O(l) ΔH = +81.2 kJ/molCalculate the ∆Hrxn for the reaction below: MgCl2 (aq) + 2 KOH (aq) ---> Mg(OH)2 (s) + 2 KCl (aq) ∆Hfo for MgCl2 (aq) = -797.1 kJ/mol ∆Hfo for KOH (aq) =-424.2 kJ/mol ∆Hfo for Mg(OH)2 (s) = -924.7 kJ/mol ∆Hfo for KCl (aq) = -419.6 kJ/mol ∆Hrxno = ? kJ Don't forget the sign and write your 4 significant figures.