H2 (9)O2 (9)H2O (g)-241.82H° (kJ/mol)ΣΗ(product)ΣΗ'(reac tan t)AH rænT in KelvinAS (surr)AS(universe)Spontaneity (S for spontaneous and NS for non-spontaneous) :|||| Calculate the AS° for the given reaction.H2O9) → H2 (9)+ 02 (9)molar ratio of the balanced chemical equation:H2 (9)O2 (9)H2O9)Substance130.6205.0188.7S° ( J/mol · K)ES(product)ES (reac tan t)%3DAS ran

Here using standard entropy and standard enthalpy of H2,O,2 and H2O ,we have to determine ∆S rxn and…

Answered: H2 (g) O2 (9) H2O (9) -241.82 H°…

H2 (g) O2 (9) H2O (9) -241.82 H° (kJ/mol) ΣΗ product) EH (reactant) ΔΗ. ran T in Kelvin AS (surr) AS (universe) Spontaneity (S for spontaneous and NS for non- spontaneous) : ||

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy

Section18.5: Entropy Changes And Spontaneity

Problem 1RC

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Question

H2 (9)
O2 (9)
H2O (g)
-241.82
H° (kJ/mol)
ΣΗ
(product)
ΣΗ'
(reac tan t)
AH ræn
T in Kelvin
AS (surr)
AS
(universe)
Spontaneity (S for spontaneous and NS for non-
spontaneous) :
||
||

Calculate the AS° for the given reaction.
H2O9) → H2 (9)
+ 02 (9)
molar ratio of the balanced chemical equation:
H2 (9)
O2 (9)
H2O9)
Substance
130.6
205.0
188.7
S° ( J/mol · K)
ES
(product)
ES (reac tan t)
%3D
AS ran

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