Having just invented a new type of calorimeter, Dr. Covey needs to determine the heat capacity of the calorimeter.  She carries out the following experiment to do this: Her empty calorimeter is at a temperature of 25.0ºC.  She adds 56.439 grams of water at a temperature of 65.6ºC to the empty calorimeter and the final temperature of the calorimeter and the water is 40ºC.   Based on this experiment, what is the heat capacity of her calorimeter assuming units of J/ºC? Enter your answer with at least 3 sig figs.

Chemistry: Principles and Reactions
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Chapter8: Thermochemistry
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Having just invented a new type of calorimeter, Dr. Covey needs to determine the heat capacity of the calorimeter.  She carries out the following experiment to do this:

Her empty calorimeter is at a temperature of 25.0ºC.  She adds 56.439 grams of water at a temperature of 65.6ºC to the empty calorimeter and the final temperature of the calorimeter and the water is 40ºC.  

Based on this experiment, what is the heat capacity of her calorimeter assuming units of J/ºC?

Enter your answer with at least 3 sig figs. 

 

Expert Solution
Step 1

Mass of water (m) = 56.439 g

Specific heat capacity of water (s) = 4.18 J/goC

Initial temperature of water = 65.6oC

Final temperature of water = 40oC

Change in temperature of water = 65.6 – 40 = 25.6oC

Amount of heat lost by water = Q = ms∆T

The value of Q can be determined as follows:

Q  =  56.439 g × 4.18 JgoC-1 × 25.6oCQ  =  6039.43 J

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