HCI(9) and HCI(aq) Match the words in the left column to the appropriate blanks in the sentences on the right. Reset fewer particles will have the higher standa occupy a smaller volume entropy at 25 °C. This can best be explained because liquid or aqueous phases have more degrees of freedom associated with movement

HCI(9) and HCI(aq) Match the words in the left column to the appropriate blanks in the sentences on the right. Reset fewer particles will have the higher standa occupy a smaller volume entropy at 25 °C. This can best be explained because liquid or aqueous phases have more degrees of freedom associated with movement

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter8: Electrochemistry And Ionic Solutions

Section: Chapter Questions

Problem 8.76E

See similar textbooks

Similar questions

What is the significance of the point in which the Fe-FeO curve crosses the CO line (at ~1000K) on the Ellingham diagram below?
Thermodynamics Quantities for Selected Substances at 298.15 K (25⁰C) Substance ∆H⁰f (kJ/mol) ∆G⁰f (kJ/mol) S (J/K-mol) Carbon C2H2(g) 226.7 209.2 200.8 CO2(g) -393.5 -394.4 213.6 Hydrogen H2(g) 0 0 130.58 Oxygen O2(g) 0 0 205.0 H2O(l) -285.83 -237.13 69.91 What is the ∆S⁰ in the combustion of ethane in the presence of excess oxygen yields carbon dioxide and water: 2C2H2(g) + 7O2(g) → 4CO2(g) + 6H2O(l) in J/K?
When nitric acid is produced industrially, nitrogen monoxide, NO, is first formed at high temperature. Bakefetr reacts NO on cooling further with oxygen to nitrogen dioxide: 2 NO(g) + O2 ⇌ 2 NO2 (g) Table 1: Thermodynamic data at 25°C. Bond ΔfHom Som Cop,m NO(g) 90.25 210.76 29.34 O2(g) 0.00 205.14 29.36 NO2(g) 33.18 240.06 37.20 1) Calculate (with all relevant intermediate calculations) the standard reaction Gibbs free energy, ΔrG25o, for reaction (1) at 25°C from the data in Table 1 2) Calculate (with all relevant intermediate calculations) the equilibrium constant K25, for reaction (1) at 25°C. 3) Industrially, however, the reaction does not proceed at 25°C but at 500°C. Therefore, calculate (with all relevant intermediate calculations) the standard reaction Gibbs free energy, ΔrG500o, for reaction (1) at 500°C under the assumption that the standard molar heat capacities, Cop, in Table 1 are independent of temperature in the interval [25°C, 500°C]
At 298K, NH4NO3 readily dissolves in water, suggesting that the change in free energy (ΔG) favors the dissolution process. However, when NH4NO3 dissolves in water, the temperature of the water decreases. The particulate diagram above attempts to provide a microscopic view of the dissolution of NH4NO3(s) considering both the change in enthalpy (ΔH) and the change in entropy (ΔS). Which of the following explains what the particle diagram is able to illustrate and why? (see attached image) a.) The particle diagram is able to illustrate that the ΔH for the dissolution of NH4NO3 is exothermic because overcoming the attractive forces between the ions requires the absorption of energy. b.) The particle diagram is able to illustrate that the ΔH for the dissolution of NH4NO3 is endothermic because forming new interactions between the ions and the water molecules releases energy. c.) The particle diagram is able to illustrate that entropy increases when NH4NO3(s) dissolves in water…
Thermodynamics Quantities for Selected Substances at 298.15 K (25⁰C) Substance ∆H⁰f (kJ/mol) ∆G⁰f (kJ/mol) S (J/K-mol) Carbon C2H2(g) 226.7 209.2 200.8 C2H4(g) 52.30 68.11 219.4 Hydrogen H2(g) 0 0 130.58 Oxygen O2(g) 0 0 205.0 H2O(l) -285.83 -237.13 69.91 3. What is the value of ∆S⁰ for the catalytic hydrogenation of ethene to ethane: C2H4(g) + H2(g) → C2H6(g) + 2H2O(l) in J/K?
Thermodynamics Quantities for Selected Substances at 298.15 K (25⁰C) Substance ∆H⁰f (kJ/mol) ∆G⁰f (kJ/mol) S (J/K-mol) Hydrogen H2(g) 0 0 130.58 Oxygen O2(g) 0 0 205.0 H2O(l) -285.83 -237.13 69.91 10. What is the ∆S⁰ in the combustion of hydrogen in the presence of excess oxygen yields water: 2H2(g) + O2(g) → 2H2O(l) in J/K?
Given below (c): Standard gibb's free energies (∆Gf0 kJ mol-1 ): UO2 = -962.7 UO22+ = -953.5 U4+ = -579.1 Fe2+ = -78.9 Fe(OH)3 ferrihydrite = -692.07 Mn2+ = -288.1 MnO2 pyrolusite = -465.1 HS- = 12.1 H+ = 0 H2O = -237.1 S0 = 0 Given: U(VI) as uraninite; UO2 (where Mn2+ = reductant; MnO2 pyrolusite = product): ∆ Gr0 = -21.3 KJ/mol E0 (emf) = 0.110 V n = 2 F = 96.42 QUESTION: Calculate Eh equation below to calculate at different pH: – Eh = E0 + (RT/nF) * lnK For U(VI) as uraninite; UO2 (where HS- = reductant; S0 = product): UO22+ + Hs- ---- > UO2 + S + H+ [A] pH 3 [B] pH 7
Heterogeneous chemical reactionConsider the following reaction to form an industrially important solid product B:A (g) ↔ B (s) + C (g) + D (g)a) How many phases are present?b) What is the maximum amount of solid product B you can make for each mole of A fed to the reactorif the reactor is operating at 400 ºC and 1 bar. Data: K = 10.43 at 400 ºC
10. What is ∆G for the decomposition of CaCO3 at 298K and a partial pressure of CO2 of 4*10-4 bar? ∆Gf0 for CaCO3(s), CaO(s) and CO2(g) are -1129 kJ/mol, -604 kJ/mol and -394 kJ/mol, respectively. CaCO3(s) → CaO(s) + CO2(g) A. 0 B. -131 kJ/mol C. 112 kJ/mol D. 131 kJ/mol E. 150 kJ/mol (Correct answer is C, I'm just looking for an explanation!).
Coiled coils are protein domains that lead to the formation of multimers (dimers,trimers, tetramers, etc.). They are found in a wide range of proteins. Here we willconsider the trimerization reaction. We may write the chemical equilibrium as3 M(aq) ⇄ T(aq)where M and T represent, respectively, the monomer and trimer species. Given that∆rG0 = −25.00 kJ mol−1 at 37 0C (with the standard state the normal one for reactionsin solution, namely c0 = 1.0 mol dm−3):A) What is the equilibrium constant for the formation of the trimer at 37 0C? B) Suppose that in a particular experiment at 37.00 0C the initial concentrations ofthe monomer if [M]0 = 2.00×10−2 µM and the initial concentration of the trimeris also [T]0 = 2.00 × 10−2 µM. What is ∆rG for the formation of the trimer atthe specified temperature? C) For the conditions given in part (B) will trimers spontaneously convert to monomers?Give a very short justification of your answer. D) Suppose that ∆rH0 and ∆rS0 are independent of the…
COMPOUND ∆Hf (kJ/mole) S° (J/K mole) MgCO3 –1111 65.86 BaCO3 –1213 112.1 MgO –601.6 27.0 BaO –548 72.1 CO2 –393.5 213.8 Calculate ∆G° for the reaction of MCO3 ---> MO + CO2 at 25°C for the alkaline earth compounds Mg and Ba
When factor (Q-S)/S is small , a crystalline solid is more likely.