he average American gets a haircut every 39 days. Is the average different for college students? The data below shows the results of a survey of 12 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 40, 27, 46, 37, 28, 32, 38, 26, 37, 42, 31, 38 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer ≠ = < > H1:H1: ? μ p Select an answer = > < ≠ The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean number of days between haircuts for college students is not significantly different from 39 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 39. The data suggest the population mean is not significantly different from 39 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is equal to 39. The data suggest the populaton mean is significantly different from 39 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 39.
he average American gets a haircut every 39 days. Is the average different for college students? The data below shows the results of a survey of 12 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 40, 27, 46, 37, 28, 32, 38, 26, 37, 42, 31, 38 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer ≠ = < > H1:H1: ? μ p Select an answer = > < ≠ The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean number of days between haircuts for college students is not significantly different from 39 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 39. The data suggest the population mean is not significantly different from 39 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is equal to 39. The data suggest the populaton mean is significantly different from 39 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 39.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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The average American gets a haircut every 39 days. Is the average different for college students? The data below shows the results of a survey of 12 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal.
40, 27, 46, 37, 28, 32, 38, 26, 37, 42, 31, 38
What can be concluded at the the αα = 0.05 level of significance level of significance?
- For this study, we should use Select an answer t-test for a population
mean z-test for a population proportion - The null and alternative hypotheses would be:
H0:H0: ? p μ Select an answer ≠ = < >
H1:H1: ? μ p Select an answer = > < ≠
- The test statistic ? z t = (please show your answer to 3 decimal places.)
- The p-value = (Please show your answer to 3 decimal places.)
- The p-value is ? ≤ > αα
- Based on this, we should Select an answer accept fail to reject reject the null hypothesis.
- Thus, the final conclusion is that ...
- The data suggest the population mean number of days between haircuts for college students is not significantly different from 39 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 39.
- The data suggest the population mean is not significantly different from 39 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is equal to 39.
- The data suggest the populaton mean is significantly different from 39 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 39.
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