he of a hucleić áčid is the nitrogen bases. True
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- Transcribe and translate the following DNA sequence (nontemplate strand): 5’-ATGGCCGGTTATTAAGCA-3’A section of template DNA has the following sequence of nitrogenous bases: 5’-CGATTACTG-3’. Which of the following sequences would be produced as a result of transcription? Group of answer choices CGTUUTCAG CGAUUACUG GCUAAUGAC GCTAATGACProvide the complementary strand and the RNA transcription product for the following DNA template segment:5'-AGGGGCCGTTATCGTT-3'
- GIVEN THE FOLLOWING DNA SEQUENCES (+) OF THE GENBANK: INDICATE WHICH IS THE TEMPLATE MOLECULE, WHICH IS THE mRNA AND THE POLYPEPTIDE THAT IS FORMED FROM THE SEQUENCE DNA 5' atgagtaaagga 3'The template strand of DNA is 3’AGGATGCACGTAC5’ The sequence of the mRNA that is made from this DNA is: A) 5’UCCUACGUGCAUG3’ B) 5'AGGATGCACGTAC 3’ C) 3’UCCUACGUGCAUG5’ D) 3’AGGAUGCACGUAC5’ E) 5’AGGAUGCACGUAC3’does anyone know how to list the RNA sequence transcribed from the DNA template sequence TTACACTTGCTTGAGAGTC.
- Which of the following endonuclease removes a length of DNA between two telomere sequences?a) EcoR1b) EcoR2c) BamHId) HindIIIList the sequences of RNA that would be transcribed from the following DNA template sequences. TTACACTTGCTTGAGAGTC ACTTGGGCTATGCTCATTA GGCTGCAATAGCCGTAGAT GGAATACGTCTAGCTAGCA5’ GGACCTATCAAAATCCTTATGCGCTAGGATAGCTAACGCATCCAC3’ This is the template strand. The +1 transcription start site is bold. Transcribe template DNA to mRNA. Make sure you write mRNA in the 5’ to 3’ direction. This is tricky – don’t assume the polymerase knows right from left. It can only synthesize new DNA in 5’>3’ direction.
- RNA polymerase transcribes the following DNA template strand: 5' ACC TTT CCG 3' What is the RNA sequence going to be?DNA is made of two strands that are antiparallel. If one strand runs from 3’ to 5’ direction the other one will go from 5’ to 3’ direction. During replication or transcription, whatever the process is, it will always follow the 5’ to 3’ direction using the 3’ to 5’ directed strand as the template strand. Therefore, if following is the DNA sequence5’-CCG ATC GCA CAA-3’a) Using this sequence as template after transcription no protein can be translated. Why? I. Presence of start codonII. Absence of start codonIII. Due to mutationb) If you want to start the translation, what change you need in the second codon (from 5’ to 3’ direction)?I. Substitution of C with GII. No changeIII. Deletion of CIV. Both I & IIITranscribe an RNA from the following DNA Template sequence:5’-CCA ATG GCA ATG ATT-3’