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- What hydrogen ion concentration (H+) (expressed in mol dm - 3 ), corresponds-to a pH of 2.60? Give your answer to two decimal places and in scientific notation(b) Calculate the pH of 0.0005 mol dm-3 ethanoic acid when its pKa = 4.75 and explain the assumptions made in the calculations CH3COOH(aq) à CH3COO-(aq) + H+(aq) Ka = pH = 3.1 (a) Define and write the expression of Kw for the dissociation of water (H2O). Kw is the ____________________ _____________ of _________________ Kw = (b) Calculate the pH of 0.1 mol dm-3 potassium hydroxide (KOH(aq)) pH = 10. Explain briefly the effect of temperature on Kw.The Ka value for benzoic acid (C6H5COOH) is 6.3×10^−5 and for phenol (C6H5OH) thevalue of Ka is 1.3×10^−10. Which is a stronger base, C6H5COO− (aq) or C6H5O− (aq)?Explain your answer (write reactions to illustrate).
- Hi pls help me with this with solution and explanation thanks! This is GenchemHello, can someone please help me with these chem questions and give me a clear step-by-step solution. Thank you very much for your help. a)The [H3O+], in M, of 10.00 mL of 0.100 M NaOH after adding 10.00 mL of indicator solution. To enter exponential values, use the format 1.0e-5. b)The [H3O+], in M, of 10.00 mL of 0.100 M HCl after adding 10.00 mL of the indicator solution. To enter exponential values, use the format 1.0e-5.Calculate the volume (ml)of concentrated ammonia and the weight (gm) of ammonium chloride respectively to be taken to prepare 100 ml of buffer solution at a pH of 10 if the final concentration of the salt is 0.20 mol. Note that the molar concentration of concentrated ammonia is equal to 14.8 mol/liter, and that the pKb of ammonia is 4.76, and the molecular weight of ammonium :chloride 53.5 g/mole.lt is about
- Give good explanation Asap Thanks You have a 0.10 M aqueous NH3 solution. Calculate a) the number of moles and b) the number of grams of NH4Cl that must be added to 500 ml. of this solution to obtain a buffer solution of pH = 9.15 Neglect the volume change from the addition of solid NHCl.Present clear legible solutions and answers thank youA solution consisting of 1.14e-4 M H2S was found to be 2.78196 % ionized. What is the Ka? See reaction belowH2S(aq) + H2O ↔HS- + H3O+ 9.100e-8 3.180e-6 0.02782 1.833e-7