15. Help Solve the 3D system by filling in the blanks correctly. Final anSwers must be supported by correct wwork.1) 5z + 6y+ z = -22) 4z - 8y+ 6z = 63) 6z + 4y-6z = 8Without doing any multiplying, I can combine equation 2 andv to eliminate thev when adding.This gives me equation 4, which is:4)- 4y =v byNow I am going to combine equation 1 and equation 3. I will need to multiplyAdding these together gives me equation 5, which is:5)v to eliminate the y's.Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 by This gives me equation 4, which is:4)- 4y =Now I am going to combine equation 1 and equation 3. I will need to multiplybyAdding these together gives me equation 5, which is:5)v to eliminate the y's.Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 bySoand then z=1.Now we take the x, and substitute into either equation 4 or equation 5, whichever is easier.so y = -1.Finally, substituting the x and y into the easiest of the first 3 equations, I get z = -1.

Given, 1) 5x+6y+z=-22)4x-8y+6z=63) 6x+4y-6z=8

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Algebra for College Students

10th Edition

ISBN:9781285195780

Author:Jerome E. Kaufmann, Karen L. Schwitters

Publisher:Jerome E. Kaufmann, Karen L. Schwitters

Chapter13: Conic Sections

Section13.5: Systems Involving Nonlinear Equations

Problem 39PS

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Concept explainers

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.

Question

15. Help

Solve the 3D system by filling in the blanks correctly. Final anSwers must be supported by correct wwork.
1) 5z + 6y+ z = -2
2) 4z - 8y+ 6z = 6
3) 6z + 4y-6z = 8
Without doing any multiplying, I can combine equation 2 and
v to eliminate the
v when adding.
This gives me equation 4, which is:
4)
- 4y =
v by
Now I am going to combine equation 1 and equation 3. I will need to multiply
Adding these together gives me equation 5, which is:
5)
v to eliminate the y's.
Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 by

This gives me equation 4, which is:
4)
- 4y =
Now I am going to combine equation 1 and equation 3. I will need to multiply
by
Adding these together gives me equation 5, which is:
5)
v to eliminate the y's.
Now let's combine equation 4 and equation 5, but we will need to multiply equation 4 by
So
and then z=1.
Now we take the x, and substitute into either equation 4 or equation 5, whichever is easier.
so y = -1.
Finally, substituting the x and y into the easiest of the first 3 equations, I get z = -1.

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