Hemoglobin, abbreviated Hgb, reacts with a certain oxide, XO, and oxygen gas, 02. Consider the following reactions and approximate standard free energy changes: Hgb + 02 = HgbO2 AG° = -70.00 kJ Hgb + XO = HgbXO AG° = -93.4 kJ Using these data, estimate the equilibrium constant value at 25 °C for the following reaction: HgbO2 + XO = HgbXO + 02 Please make sure to use 4 sig. figs throughout your calculations.

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Chapter17: Spontaneity, Entropy, And Free Energy
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Problem 22Q: What information can be determined from G for a reaction? Does one get the same information from G,...
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Hemoglobin, abbreviated Hgb, reacts with a certain oxide, XO, and oxygen gas, 02. Consider the following
reactions and approximate standard free energy changes:
ΔG° = -70.00 kJ
AG° = -93.4 kJ
Hgb + 02 = Hgb02
Hgb + XO = HgbXO
Using these data, estimate the equilibrium constant value at 25 °C for the following reaction:
Hgbo2 + XO = HgbXO + 02
Please make sure to use 4 sig. figs throughout your calculations.
Answer: -23.40
The correct answer is: 12634.20
Transcribed Image Text:Hemoglobin, abbreviated Hgb, reacts with a certain oxide, XO, and oxygen gas, 02. Consider the following reactions and approximate standard free energy changes: ΔG° = -70.00 kJ AG° = -93.4 kJ Hgb + 02 = Hgb02 Hgb + XO = HgbXO Using these data, estimate the equilibrium constant value at 25 °C for the following reaction: Hgbo2 + XO = HgbXO + 02 Please make sure to use 4 sig. figs throughout your calculations. Answer: -23.40 The correct answer is: 12634.20
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