A student determines the value of the equilibrium constant to be 3.88×1013 for the following reaction. 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Based on this value of Keq: G° for this reaction is expected to be (greater, less)  than zero. Calculate the free energy change for the reaction of 1.80 moles of HCl(g) at standard conditions at 298K.     G°rxn =  kJ

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