Here are some data collected on a sample of cesium exposed to various energies of light. Light energy Electron emitted? Electron KE (eV) (eV) 2.12 2.13 2.14 2.15 2.16 no no yes yes yes - 0 0.01 0.02 *Note that 1 eV (electron volt) = 1.60 × 10-¹⁹ J.

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter5: Electron Configurations And The Periodic Table
Section: Chapter Questions
Problem 114QRT
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What is the threshold frequency ν0 of cesium?

 

Electrons are emitted from the surface of a metal
when it's exposed to light. This is called the
photoelectric effect. Each metal has a certain
threshold frequency of light, below which nothing
happens. Right at this threshold frequency, an
electron is emitted. Above this frequency, the
electron is emitted and the extra energy is
transferred to the electron.
The equation for this phenomenon is
KE= hv - hvo
-
where KE is the kinetic energy of the emitted
electron, h 6.63 × 10-34 J.s is Planck's
constant, is the frequency of the light, and vis
the threshold frequency of the metal.
Also, since E = hv, the equation can also be
written as
KE=E-O
where E is the energy of the light and is the
binding energy of the electron in the metal.
Transcribed Image Text:Electrons are emitted from the surface of a metal when it's exposed to light. This is called the photoelectric effect. Each metal has a certain threshold frequency of light, below which nothing happens. Right at this threshold frequency, an electron is emitted. Above this frequency, the electron is emitted and the extra energy is transferred to the electron. The equation for this phenomenon is KE= hv - hvo - where KE is the kinetic energy of the emitted electron, h 6.63 × 10-34 J.s is Planck's constant, is the frequency of the light, and vis the threshold frequency of the metal. Also, since E = hv, the equation can also be written as KE=E-O where E is the energy of the light and is the binding energy of the electron in the metal.
Here are some data collected on a sample of cesium exposed to various energies of light.
Light energy Electron emitted? Electron KE
(eV)
(eV)
2.12
2.13
2.14
2.15
2.16
no
no
yes
yes
yes
0
0.01
0.02
*Note that 1 eV (electron volt) = 1.60 × 10-¹⁹ J.
Transcribed Image Text:Here are some data collected on a sample of cesium exposed to various energies of light. Light energy Electron emitted? Electron KE (eV) (eV) 2.12 2.13 2.14 2.15 2.16 no no yes yes yes 0 0.01 0.02 *Note that 1 eV (electron volt) = 1.60 × 10-¹⁹ J.
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