HF(ag) + H2O(1) 2 H3O* (aq) + F (aq) Ka 6.3 x 10-4 at 25°C The acid ionization equilibrium for HF is represented by the chemical equation above. A student claims tha the pH of a solution that contains 0.100 M HF(aq) and 0.100 M NaF(aq) will change only slightly when small amounts of acids or bases are added. Which of the following pairs of equations can the student use to justify the claim? HF (аq) + ОН (ад) —> НәО(1) +F (ag) and A

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.87QE
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Question 49
-4
HF(aq) + H20(1) 2 H;O* (aq) +F (aq)
Ka = 6.3 x 10 at 25°C
The acid ionization equilibrium for HF is represented by the chemical equation above. A student claims that
the pH of a solution that contains 0.100 M HF(aq) and 0.100 M NaF(aq) will change only slightly
when small amounts of acids or bases are added. Which of the following pairs of equations can the student
use to justify the claim?
HF(aq) + OH (aq) → H2O(1) +F¯(aq) and
A
ОН (ад) + Hзо" (аq) —> 2 Н,0 ()
H3O* (aq) + OH (aq) → 2 H2O(1) and
F (ag) + H30*(ag) → HF(aq) + H2O(1)
В
НF (ад) + ОН (ад)
F (aq) + H20() — HF(aq) + Он (ад)
- H2O(1) + F (aq) and
C
НF (ад) + ОН (аq) —> Н2О(1) + F (аq) and
F (ag) + H3O*(ag) → HF(aq) + H,O(1)
D
Transcribed Image Text:Question 49 -4 HF(aq) + H20(1) 2 H;O* (aq) +F (aq) Ka = 6.3 x 10 at 25°C The acid ionization equilibrium for HF is represented by the chemical equation above. A student claims that the pH of a solution that contains 0.100 M HF(aq) and 0.100 M NaF(aq) will change only slightly when small amounts of acids or bases are added. Which of the following pairs of equations can the student use to justify the claim? HF(aq) + OH (aq) → H2O(1) +F¯(aq) and A ОН (ад) + Hзо" (аq) —> 2 Н,0 () H3O* (aq) + OH (aq) → 2 H2O(1) and F (ag) + H30*(ag) → HF(aq) + H2O(1) В НF (ад) + ОН (ад) F (aq) + H20() — HF(aq) + Он (ад) - H2O(1) + F (aq) and C НF (ад) + ОН (аq) —> Н2О(1) + F (аq) and F (ag) + H3O*(ag) → HF(aq) + H,O(1) D
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