Hi, I am in physics I and I'm trying to understand this word problem. It saids that a 6.0-m uniform board is supported by two sawhorses 4.0m apart. A 32kg child walks on the board to 1.4 m beyond the right support when the board start to tip. a.) Find the mass of the boardb.) Then he walks back 0.40m and stands still. Find the forces exerted by the supports at this time. (use the mass found in part a). Please be detailed of how this works. Its a harder problem for me to understand. Thank you!

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Asked Nov 3, 2019
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Hi, I am in physics I and I'm trying to understand this word problem. It saids that a 6.0-m uniform board is supported by two sawhorses 4.0m apart. A 32kg child walks on the board to 1.4 m beyond the right support when the board start to tip. 

a.) Find the mass of the board

b.) Then he walks back 0.40m and stands still. Find the forces exerted by the supports at this time. (use the mass found in part a).

 

Please be detailed of how this works. Its a harder problem for me to understand. Thank you!

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Expert Answer

Step 1

a)

the torque on both side of the right sawhorses must be same  from the center of the board and from the child.

the equilibrium condition is 

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Mg = mgr

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Step 2

substitute the given values to c...

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6.0m Mg 2 -1.4m (32kg)g(1.4m) 2(32kg)g(1.4m) м 1.6m = 56.0kg

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