  # Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours.I have already found the angular speed ω= 7.3×10−5  rad/s   and the point on the equator v= 460 ms.  What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)

Question

Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours.

I have already found the angular speed

ω= 7.3×10−5  rad/s   and the point on the equator v= 460 ms.

What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)

check_circleExpert Solution
Step 1

The angle formed between the equator and pole is 90 degrees. The arc ratio will be same as the ratio between angles.

Draw the diagram as shown below.

Step 2

The angle between equator and the location of the point and the angle between pole and the location of the point is:

Step 3

Now, the radius from the axis of ...

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