Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours.I have already found the angular speed ω= 7.3×10−5  rad/s   and the point on the equator v= 460 ms.  What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)

Question
Asked Oct 31, 2019

Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours.

I have already found the angular speed 

ω= 7.3×10−5  rad/s   and the point on the equator v= 460 ms.  

What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)

 

check_circleExpert Solution
Step 1

The angle formed between the equator and pole is 90 degrees. The arc ratio will be same as the ratio between angles.

Draw the diagram as shown below.

Pole
Equator
help_outline

Image Transcriptionclose

Pole Equator

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Step 2

The angle between equator and the location of the point and the angle between pole and the location of the point is:

2
ө
(90)
=36
2
а
5
(90°)
=54
help_outline

Image Transcriptionclose

2 ө (90) =36 2 а 5 (90°) =54

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Step 3

Now, the radius from the axis of ...

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