Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours.I have already found the angular speed ω= 7.3×10−5 rad/s and the point on the equator v= 460 ms. What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)
Hi, in physics I they have The earth's radius is 6.37×106m; it rotates once every 24 hours.
I have already found the angular speed
ω= 7.3×10−5 rad/s and the point on the equator v= 460 ms.
What I'm trying to understand is what is the speed of a point on the earth's surface located at 2/5 of the length of the arc between the equator and the pole, measured from equator? (Hint: what is the radius of the circle in which the point moves?)
The angle formed between the equator and pole is 90 degrees. The arc ratio will be same as the ratio between angles.
Draw the diagram as shown below.
Image Transcriptionclose
Pole Equator
The angle between equator and the location of the point and the angle between pole and the location of the point is:
Image Transcriptionclose
2 ө (90) =36 2 а 5 (90°) =54
Now, the radius from the axis of ...
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