A compound X is to be determined by UV/visible spectrophotometry. A calibration curve is constructed from standard solutions of X with the following results:  - 0.50 ppm, A = 0.24; - 1.5 ppm, A = 0.36; - 2.5 ppm, A = 0.44; - 3.5 ppm, A = 0.59; and - 4.5 ppm, A = 0.70. Find the following: A. Slope and intercept of the calibration curve B. The mean concentration of the solution of unknown X concentration if the absorbance of 3 replicates are A = 0.29, A = 0.30 and A = 0.32. C. The standard deviation in the concentration of X

Fundamentals Of Analytical Chemistry
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ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter24: Introduction To Spectrochemical Methods
Section: Chapter Questions
Problem 24.28QAP
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A compound X is to be determined by UV/visible spectrophotometry.

A calibration curve is constructed from standard solutions of X with the following results: 

- 0.50 ppm, A = 0.24;
- 1.5 ppm, A = 0.36;
- 2.5 ppm, A = 0.44;
- 3.5 ppm, A = 0.59; and
- 4.5 ppm, A = 0.70.


Find the following:
A. Slope and intercept of the calibration curve
B. The mean concentration of the solution of unknown X concentration if the absorbance of 3 replicates are A = 0.29, A = 0.30 and A = 0.32.
C. The standard deviation in the concentration of X

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Follow-up Question

For the calculation of sd, shouldn't it be (0.97-1.09) and so on... because 0.97 = x and 1.09 = mean? 

 

and the formula for sd is squared of the summation of (x-mean)^2 divide by n?

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Follow-up Question

For the standard equation, shouldn't it be  (0.97-1.09) and so on... because (x-mean)

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Follow-up Question

For C, shouldn't be like this?

3.
Mean
standard deviation ()
in conc".
of x
t
deviation
u = population mean
N
C
to tel
each valce from nuan
{(x-4)
N
size of population
concentrations.
0.5 +1.55 +2.5+3.5+ 4.5
24 + 1 + 0 + 1 + 4
5
5
1.41
(0.5-2.5) ²+ (1.5-2.5) ²+12.5-2.5) ²7 (3.5-2-5) 2² +4.5-2.592
2
Transcribed Image Text:3. Mean standard deviation () in conc". of x t deviation u = population mean N C to tel each valce from nuan {(x-4) N size of population concentrations. 0.5 +1.55 +2.5+3.5+ 4.5 24 + 1 + 0 + 1 + 4 5 5 1.41 (0.5-2.5) ²+ (1.5-2.5) ²+12.5-2.5) ²7 (3.5-2-5) 2² +4.5-2.592 2
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Follow-up Question

How did you get y=0.115x+0.1785? And r^2= 0.9935

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