Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter9: Energy And Chemistry
Section: Chapter Questions
Problem 9.41PAE: 9.41 Under what conditions does the enthalpy change equal the heat of a process?
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Hello,
how did you obtain the values of enthalpy change for the products and reactants?
Thanks!
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Follow-up Question
Could you please show the work for the highlighted enthalpy values? I have the tabulated values for bond energies but I'd just like to see it step-by-step. Thank you.
Solution
by Bartleby ExpertFollow-up Question
I meant these values.
Transcribed Image Text:bartleby.com/solution.
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Explanation of Solution
The given reaction is:
& ASK
AH°R = 5 x AHO
+
CHAT
4NH3(g)+6NO(g) → 5N₂(g)+6H₂O(g)
The mathematical expression for the standard
enthalpy change value at room temperature is:
AH°R = ΣnH°(products) - pH (reactants)
Dut +L
+6×AHO
f.№₂(g)
f.H₂O(g)
The enthalpy change of N₂(g) = 0 kJ/mole
The enthalpy change of H₂O(g) = −241.8 kJ/mole
The enthalpy change of NO(g) = 91.3 kJ/mole
The enthalpy change of NH3(g) = −45.9 kJ/mole
Put the values,
=
AHR
-1816 kJ/mole
Now, value of Ang = (6+5) − (6 + 4)
= 1
48
VX MA
6x AH
AHOR = 5 x (0kJ/mole) + 6× (-241.8 kJ/mole) - 6 >
x (-45.9 kJ/mole)
The mathematical expression of change in
internal energy is:
AU=AHR - Ang RT
f,NO(g
Solution
by Bartleby ExpertKnowledge Booster
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