how is the 0.071s^2 + 0.389s + 0.727 was computed through regression? can someone explain? Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then,20406080100S5.5611.1116.6722.2227.78d5.113.727.244.266.4Step 2use the regression capabilities of a graphing utility to find the model of the form d (s) = as? + bs + cthen,d (s) = 0.071s² + 0. 389s + 0. 727d(s)Now, calculating the minimum value of T then substitute d (s) into the equation T (s) =+ 55T (s) = (0.071s2² + 0. 389s + 0. 727) + 35.5T (s) = 0.071s + 0. 389 + 6.227

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Answered: how is the 0.071s^2 + 0.389s + 0.727…

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how is the 0.071s^2 + 0.389s + 0.727 was computed through regression? can someone explain?

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.3: Lines

Problem 32E

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Question

how is the 0.071s^2 + 0.389s + 0.727 was computed through regression? can someone explain?

Now, substituting v = 20, 40, 60, 80 and 100 respectively into the obtained equation then,
20
40
60
80
100
S
5.56
11.11
16.67
22.22
27.78
d
5.1
13.7
27.2
44.2
66.4
Step 2
use the regression capabilities of a graphing utility to find the model of the form d (s) = as? + bs + c
then,
d (s) = 0.071s² + 0. 389s + 0. 727
d(s)
Now, calculating the minimum value of T then substitute d (s) into the equation T (s) =
+ 55
T (s) = (0.071s2² + 0. 389s + 0. 727) + 3
5.5
T (s) = 0.071s + 0. 389 + 6.227

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