How long does it take a 750-WW coffeepot to bring to a boil 0.85 LL of water initially at 18 ∘C∘C? Assume that the part of the pot which is heated with the water is made of 360 gg of aluminum, and that no water boils away. Ignore the heat loss to the surrounding environment. The value of specific heat for water is 4186 J/kg⋅C∘J/kg⋅C∘ and for aluminum is 900 J/kg⋅C∘J/kg⋅C∘.
Latent heat and phase change
A physical process in which a conversion among the basic states or phases of matter, i.e., solid, liquid, and gas takes place under the effect of a certain temperature and pressure is referred to as a phase change. Generally, the phase change of a substance occurs when heat transfer takes place between the substance and its surroundings. Based on the direction in which heat transfer takes place, different types of phase changes can occur.
Triple Point of Water
The branch of physics in which observer deals with temperature related properties is called thermodynamics.
Boiling Point of Water
Everyday examples of boiling is, boiling milk, heating water. One would have observed that when we heat water it goes through various stages and at one point bubbles show in water, and water keeps splashing with bubbles bursting, we in layman terms say that water is boiling.
Freezing Point of Water
In general, the freezing point of water is 0° Celsius, or 32° Fahrenheit. This is the temperature at which water will ordinarily change from its liquid state to its solid state (ice). However, there are certain conditions that can affect the freezing point of water. For example, a liquid may be supercooled or contain impurities so that it does not freeze at the ordinary freezing point.
How long does it take a 750-WW coffeepot to bring to a boil 0.85 LL of water initially at 18 ∘C∘C? Assume that the part of the pot which is heated with the water is made of 360 gg of aluminum, and that no water boils away. Ignore the heat loss to the surrounding environment. The value of specific heat for water is 4186 J/kg⋅C∘J/kg⋅C∘ and for aluminum is 900 J/kg⋅C∘J/kg⋅C∘.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
