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How many grams of AlCl3 are required to make 241.4 grams of Al(OH)3? 3Mg(OH)2 + 2AlCl3 => 3MgCl2 + 2Al(OH)3

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter12: Gravimetric Methods Of Analysis

Section: Chapter Questions

Problem 12.14QAP

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Question

How many grams of AlCl₃ are required to make 241.4 grams of Al(OH)3?

3Mg(OH)2 + 2AlCl3 => 3MgCl2 + 2Al(OH)3

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