Question
Asked Sep 27, 2019

how many grams of KMnO4correspond to 3.13 x 1022 formula units of KMnO4? Avogrado's number is 6.02 x 1023

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Expert Answer

Step 1

Given,

Formula units of KMnO4 = 3.13 × 1022

Avogadro’s number = 6.02 × 1023

Moles in 3.13 x 1022 formula units of KMnO4 can be calculated as:

6.02 x 1023 units are present in
1 mol of KMnO4
1 mol
:. 3.13 x 1022 units are present in
x 3.13 x 1022 units
6.02 x 1023 units
= 0.052 mol
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6.02 x 1023 units are present in 1 mol of KMnO4 1 mol :. 3.13 x 1022 units are present in x 3.13 x 1022 units 6.02 x 1023 units = 0.052 mol

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Step 2

Grams of KMnO4 in 0.052 mol can ...

Molar mass of KMnO4 = 39 + 55 (4x16) = 158 g/mol
Mass
Moles
Molar mass
Mass Moles x Molar mass
Mass 0.052 mol x 158 g/mol
Mass 8.216 g
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Molar mass of KMnO4 = 39 + 55 (4x16) = 158 g/mol Mass Moles Molar mass Mass Moles x Molar mass Mass 0.052 mol x 158 g/mol Mass 8.216 g

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