How many grams of Na3PO4 in solution in excess after the reaction 1s complete?Hint - determine moles you started with and subtract moles that were consumed in thereaction to get moles remaining in solution then convert to grams. 2.Volume of 0,100 M Na3PO4 solution used30 mL30ML3.Initial burette volume of CaCl2 solution.6 mL20.620.6 m L40.6 mL4.Final burette volume of CaCl2 solution20 mL20 mLVolume of unknown CaCl2 solution usedMass of filter paper.381 g356 g.453 g.383 9Mass of filter paper + Ca3(PO4)2 precipitate.072 9.027 9Mass of Ca3(PO4)2 precipitate recovered000232 mol0000 871 molMoles of Ca3(PO4)2 recovered000261 mol.000696 molMoles of CaCl2 consumed in reaction.0348 M,01305,013 05 MMolarity of unknown CaCl2 solution0239 M%3DAverage Value for Molarity of Unknown CaCl2 solution

The equation is 2Na3PO4+3CaCl2---->Ca3(PO4)2 +6 NaCl From stoichiometry of the reaction,…

How many grams of Na3PO4 in solution in excess after the reaction 1s complete? Hint - determine moles you started with and subtract moles that were consumed in the reaction to get moles remaining in solution then convert to grams.

How many grams of Na3PO4 in solution in excess after the reaction 1s complete? Hint - determine moles you started with and subtract moles that were consumed in the reaction to get moles remaining in solution then convert to grams.

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter7: Solutions And Colloids

Section: Chapter Questions

Problem 7.44E

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

100%

How many grams of Na₃PO₄ in solution in excess after the reaction 1s complete?
Hint - determine moles you started with and subtract moles that were consumed in the
reaction to get moles remaining in solution then convert to grams.

2.
Volume of 0,100 M Na3PO4 solution used
30 mL
30ML
3.
Initial burette volume of CaCl2 solution
.6 mL
20.6
20.6 m L
40.6 mL
4.
Final burette volume of CaCl2 solution
20 mL
20 mL
Volume of unknown CaCl2 solution used
Mass of filter paper
.381 g
356 g
.453 g
.383 9
Mass of filter paper + Ca3(PO4)2 precipitate
.072 9
.027 9
Mass of Ca3(PO4)2 precipitate recovered
000232 mol
0000 871 mol
Moles of Ca3(PO4)2 recovered
000261 mol
.000696 mol
Moles of CaCl2 consumed in reaction
.0348 M
,01305
,013 05 M
Molarity of unknown CaCl2 solution
0239 M
%3D
Average Value for Molarity of Unknown CaCl2 solution

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