How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with 1.15 liters of a 2.75 molar potassium chromate K2CrO4solution Pb(NO3)2 + K2CrO4 PbCrO4 + 2KNO3 108 g 681 g 639 g 362 g
How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with 1.15 liters of a 2.75 molar potassium chromate K2CrO4solution Pb(NO3)2 + K2CrO4 PbCrO4 + 2KNO3 108 g 681 g 639 g 362 g
Introductory Chemistry: A Foundation
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ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
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Chapter15: Solutions
Section: Chapter Questions
Problem 35QAP: 35. For each of the following solutions, the mass of solute is given, followed by the total volume...
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How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with 1.15 liters of a 2.75 molar potassium chromate K2CrO4solution
- Pb(NO3)2 + K2CrO4 PbCrO4 + 2KNO3
- 108 g
- 681 g
- 639 g
- 362 g
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