   # Aspirin, C 6 H 4 (OCOCH 3 ) CO 3 H, is produced by the reaction of salicylic acid, C 6 H 4 (OH)CO 2 H, and acetic anhydride, (CH 3 CO) 2 O (page 182). C 6 H 4 (OH)CO 3 H(s) + (CH 3 CO) 3 O(l) → C 6 H 4 (OCOCH 3 )CO 2 H(s) + CH 3 CO 2 H(l) If you mix 100. g of each of the reactants, what is the maximum mass of aspirin that can be obtained ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 18PS
Textbook Problem
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## Aspirin, C6H4 (OCOCH3) CO3H, is produced by the reaction of salicylic acid, C6H4(OH)CO2H, and acetic anhydride, (CH3CO)2O (page 182).C6H4(OH)CO3H(s) + (CH3CO)3O(l) → C6H4(OCOCH3)CO2H(s) + CH3CO2H(l)If you mix 100. g of each of the reactants, what is the maximum mass of aspirin that can be obtained

Interpretation Introduction

Interpretation:

The maximum mass of product (aspirin) that can be obtained in the given reaction should be determined.

Concept introduction:

• The number of moles of any substance can be determined  using the equation,

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.

### Explanation of Solution

Aspirin can be obtained by the reaction of salicylic acid C6H4(OH)CO2H, and acetic anhydride (CH3CO)2O, and the balanced chemical equation for the reaction is C6H4(OH)CO2H(s)+(CH3CO)2O(l)C6H4(OCOCH3)CO2H(s)+CH3CO2H(l)

To find the mass of product formed in the reaction, the amount of each reactant involved in the given reaction should be determined.

Therefore,

AmountofC6H4(OH)CO2H =100gC6H4(OH)CO2H×1molC6H4(OH)CO2H138.121g=0.72400molC6H4(OH)CO2HAmountof(CH3CO)2O =100g(CH3CO)2O×1mol(CH3CO)2O102

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