How many grams of solid Ca3(PO4)2 can be formed from a reaction of 51.8 mL of 0.754 M CaCl2 and 21.5 mL of 1.04 M Na3PO4?   Why can't 4.04 g of solid Ca3(PO4)2 be formed under these conditions? This amount is (greater than, less than, or equal to) the theoretical yield.

Chemistry: An Atoms First Approach
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ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter5: Stoichiometry
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How many grams of solid Ca3(PO4)2 can be formed from a reaction of 51.8 mL of 0.754 M CaCl2 and 21.5 mL of 1.04 M Na3PO4?

 

Why can't 4.04 g of solid Ca3(PO4)2 be formed under these conditions?

This amount is (greater than, less than, or equal to) the theoretical yield.
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