Diiodine pentaoxide oxidizes carbon monoxide to carbon dioxide under room conditions, yielding iodine as the sec- ond product: 1,O3(s) + 5 CO(g) → L(s) + 5 CO2(g) This can be used in an analytical method to measure the amount of carbon monoxide in a sample of air. Determine the oxidation numbers of the atoms in this equation. Which species is oxidized and which is reduced?

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
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Diiodine pentaoxide oxidizes carbon monoxide to carbon
dioxide under room conditions, yielding iodine as the sec-
ond product:
1,O3(s) + 5 CO(g) → L(s) + 5 CO2(g)
This can be used in an analytical method to measure the
amount of carbon monoxide in a sample of air. Determine
the oxidation numbers of the atoms in this equation.
Which species is oxidized and which is reduced?
Transcribed Image Text:Diiodine pentaoxide oxidizes carbon monoxide to carbon dioxide under room conditions, yielding iodine as the sec- ond product: 1,O3(s) + 5 CO(g) → L(s) + 5 CO2(g) This can be used in an analytical method to measure the amount of carbon monoxide in a sample of air. Determine the oxidation numbers of the atoms in this equation. Which species is oxidized and which is reduced?
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