How many milliliters of 0.05 M solution (Ca (NO3) should be mixed with pure water to obtain 500 g of solution with a concentration of 20 ppm calcium ions? (40 = Ca; mol total load)
How many milliliters of 0.05 M solution (Ca (NO3) should be mixed with pure water to obtain 500 g of solution with a concentration of 20 ppm calcium ions? (40 = Ca; mol total load)
Chapter13: Titrations In Analytical Chemistry
Section: Chapter Questions
Problem 13.6QAP
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Transcribed Image Text:How many milliliters of 0.05 M solution (Ca
(NO3) should be mixed with pure water to
obtain 500 g of solution with a
concentration of 20 ppm calcium ions? (40
= Ca; mol total load)
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