How many milliliters of 0.475 M KOH solution are needed to completely neutralize 38.0 mL of 0.231 M HI solution? The reaction is KOH(aq) + HI(ag) → KI(aq) + H2O(1) i mL eTexthook and Media

World of Chemistry, 3rd edition
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ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter16: Acids And Bases
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How many milliliters of 0.475 M KOH solution are needed to completely neutralize 38.0 mL of 0.231 M HI solution? The reaction is
KOH(aq) + HI(ag) → KI(aq) + H2O(1)
i
mL
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Transcribed Image Text:How many milliliters of 0.475 M KOH solution are needed to completely neutralize 38.0 mL of 0.231 M HI solution? The reaction is KOH(aq) + HI(ag) → KI(aq) + H2O(1) i mL eTextbook and Media Attempts: 0 of 15 used Submit Answer Save for Later 1 étv S k ост 14 MacBook Air
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